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Forrest Pfeffer

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3y ago
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12y ago

The general slope-intercept format for the equation of a straight line is, y = mx + c where m is the slope and c is the y-intercept (when x = 0)

When y = 4x - 1 then the slope of this line is 4 and the slope of any parallel line is also 4.

The equation of any line parallel to y = 4x - 1 is y = 4x + c ....where c can have any positive or negative value and, of course, is not equal to -1.

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Q: What is the slope of the line parallel to y equals 4x-1?
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What is the equation of the line that passes through 1 2 and is parallel to the line whose equation is 4x plus y minus 1 equals 0?

As the second line is parallel to the first then the slopes of both lines are the same. 4x + y - 1 = 0 : y = -4x + 1 : Therefore the slope is -4. Using the standard slope-intercept equation of y = mx + c for the second line gives :- 2 = -4x1 + c : 2 = -4 + c : c = 2 + 4 = 6. Therefore the equation of the second line is y = -4x + 6. (Or y + 4x - 6 = 0)


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