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What is the slope of the tangent to the curve x squared plus y squared equals 26 at x 0 equals 4 in the first quadrant. Round the answer to 3 decimal places.?
Wiki User
∙ 6y ago
Assuming you mean the tangent at x = 4 of x² + y² = 26 then:
x² + y² = 26
→ y² = 26 - x²
→ y = √(26 - x²)
→ slope = dy/dx
= d/dx √(26 - x²)
= -x/√(26 - x²)
At x = 4:
slope = -4/√(26 - 4²) = -1.26491106.... ≈ -1.265
Wiki User
∙ 6y ago
Wiki User
∙ 6y agoIt is -1.265
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