12
The smallest is -1
1 and 13.
The sum of the digits is 6.
integers are a, a + 1 and a + 2. a + 5(a + 2) = -244 ie 6a = -234 so a = -39 and the other two are -40 and -41.
12
The smallest is -1
It is -2.
2, 2, 2, 2 and 3. Sum = 11
1 and 13.
The sum of the digits is 6.
45 if the smallest is a, then the numbers are a, a+2, a+4, a+6, a+8, a+10 a + (a+2) + (a+4) + (a+6) + (a+8) + (a+10) = 300 6a + 30 = 300 6a = 270 a = 45
three consecutives numbers: a = smallest a+2 a+4 14 less = -14 than twice the smallest = 2a so... a+a+2+a+4=-14+2a 3a+6=-14+2a 3a-2a=-14-6 a=-20 answer: smallest = -20 greatest = -16
Add up the shortest possible list of numbers, and make each of them as small as possible.
The numbers 4 and 8 (4 x 8 = 32) sum to 12. The numbers 2 and 16 (2 x 16 = 32) sum to 18. There are no other factors which are integers, so 4 and 8 is the answer.
integers are a, a + 1 and a + 2. a + 5(a + 2) = -244 ie 6a = -234 so a = -39 and the other two are -40 and -41.
Suppose the smallest integer is A. The next two even numbers are A+2 and A+4. Using the information supplied we can form an equation: 2A - 14 = A + A+2 + A+4 Rearranging: 2A - 14 = 3A + 6 -20 = A So the three integers are -20, -18 and -16.