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To find the square root of 2 × 2 × 5 × 7 × 7 × 5 you can re-arrange the multiplication into two groups by taking each prime in turn in pairs and splitting the pair into one in each group, and the primes in each group multiplied together give the square root.

In 2 × 2 × 5 × 7 × 7 × 5 there is:

1 pair of 2s, so put one 2 in each group, the two groups at this stage are both {2}

1 pair of 5s, so put one 5 in each group, the two groups at this stage are now both {2 × 5}

1 pair of 7s, so put one 7 in each group the two groups at this stage are now both {2 × 5 × 7}

There are no more primes left at this stage, so the two groups are both {2 × 5 × 7}

As the two groups are the same and they are multiplied together to get the original number, the square root of the original number is the value of one of the groups; thus the square root of 2 × 2 × 5 × 7 × 7 × 5 is 2 × 5 × 7 = 70.

This can be done by rearrangement of the primes (in the prime factorisation) into the two groups:

√(2 × 2 × 5 × 7 × 7 × 5) = √((2 × 5 × 7) × (2 × 5 × 7)) = √((2 × 5 × 7)²) = 2 × 5 × 7 = 70.

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7y ago
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7y ago

2x2x5x7x7x5 = 4900. The square root of 4900 = 70

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Q: What is the square root of 2 x 2 x 5 x7 x 7 x 5?
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