To find the square root of 2 × 2 × 5 × 7 × 7 × 5 you can re-arrange the multiplication into two groups by taking each prime in turn in pairs and splitting the pair into one in each group, and the primes in each group multiplied together give the square root.
In 2 × 2 × 5 × 7 × 7 × 5 there is:
1 pair of 2s, so put one 2 in each group, the two groups at this stage are both {2}
1 pair of 5s, so put one 5 in each group, the two groups at this stage are now both {2 × 5}
1 pair of 7s, so put one 7 in each group the two groups at this stage are now both {2 × 5 × 7}
There are no more primes left at this stage, so the two groups are both {2 × 5 × 7}
As the two groups are the same and they are multiplied together to get the original number, the square root of the original number is the value of one of the groups; thus the square root of 2 × 2 × 5 × 7 × 7 × 5 is 2 × 5 × 7 = 70.
This can be done by rearrangement of the primes (in the prime factorisation) into the two groups:
√(2 × 2 × 5 × 7 × 7 × 5) = √((2 × 5 × 7) × (2 × 5 × 7)) = √((2 × 5 × 7)²) = 2 × 5 × 7 = 70.
square root of 20 = square root of 4 * square root of 5. square root of 4 = 2, so your answer is 2 square root of 5.
.5
0.4
24
It is 2*sqrt(5).
2.5
the square root of 2: 1.000 the square root of 5: 2.236 hope it helps
square root of 20 = square root of 4 * square root of 5. square root of 4 = 2, so your answer is 2 square root of 5.
2
.5
20 is 5x4 so we can simplify it like this: ____ ______ / = / \/ 20 \/ 5 x 4 Also note that: ____ / = 2 \/ 4 So... ____ ____ / = / \/ 20 2 \/ 5
0.4
I will use "root" as a symbol for square root. I assume you want to get rid of the square root in the denominator; this will usually bring some square root into the numerator.If you have the square root by itself, or as a factor, multiply numerator and denominator by this square root. Example:3 / root(2) = 3 x root(2) / root(2) x root(2) = 3 x root(2) / 2.If the square root is added or subtracted with something else, multiply with a "complement", as in the following example:1 / root(2) + 5The "complement" is the same expression, but changing the plus sign to a minus sign. Multiply numerator and denominator aby root(2) - 5:root(2) - 5 / (root(2) + 5)(root(2) - 5)= (root(2) - 5) / (2 - 25)= (root(2) - 5) / -23= -(root(2) - 5) / 23
24
It is 2*sqrt(5).
Square root of 6
=SQRT(5)*SQRT(2)+SQRT(8) is 5.99070478491457