It would be 8 + 3 = 11 kilometres West. What is missing from the question is the starting point? If the ending points were given, we would be able to reverse back to the unknown starting point.
The starting point was 11 km east of the finishing point.
3 km 1 km = 1000 meters 1 meter = 0.001 km
6 Kilo to Unit (meter) = 3 Unit to Milli = 3 Total = 6
3 km = 3000 mTo convert from km to m, multiply by 1000.
There are 1000 meters per 1 KM. So 3 KM would be 3000 Meters.
There are 4,828.032 kilometers in 3,000 miles. 3,000 miles x 1.609344 kilometers/1 mile = 4,828.032 kilometers 1 mile = 1.609344 kilometers
1 km east
The final displacement would be 3 km east of the starting point.
100 km/hr x 3 hrs = 300 km from starting point
Northeast.
1km Reason: East and West are equal and opposite directions so if he goes 3km one way and then 2km back the other way he is only 1km away from where he started (3-2)
Kyoto will be 4 blocks west with reference to his/her starting point
standing on the start point
A vehicle that is traveling at 94 km/hr travels west from 1:00 p.m. to 3:30 p.m. That's 2 and 1/2 hours of travel time at 94 km/hr. The car will travel 94 km/hr times 2 1/2 hr or 235 km in the time specified. That means the car will be that much farther west than it was at the start, which was 17 km west of a school. Add the distance from the school to the starting point of the vehicle and you'll know where the car will be at the end of the observation period. 235 km + 17 km = 252 km west of the school.
3 kilometres!
It is a total journey of 11 kilometres, resulting in a displacement of 5 km west.
3 blocks west
Relative to the starting point, the coordinates of the end point are (10-7, 5) or (3, 5) So the magnitude of the resultant vector is sqrt(32 + 52) = sqrt(9 + 25) = sqrt(34) = approx 5.83 km. The bearing (measured from North) is arctan(3/5) = arctan(0.6) = 031 degrees.