Sum = 42 Count = 6 Mean = Sum/Count = 42/6 = 7
6+9= 15
It is: 3+6 = 9
The sum of 9 and -6 is 3.
3 and 6, Sum, 3 + 6 = 9 Product, 3 x 6 = 18
3 and 9 Difference: 9-3=6 Sum: 9+3=12
Sum = 42 Count = 6 Mean = Sum/Count = 42/6 = 7
6+9= 15
9
There is no sequence of adds or subtracts of 5, 6, 8, 9, and 10 that sum to 1. Check it with this C++ code... for (int i=0; i<32; ++i) { int sum = 0; if (i&1) sum += 5; else sum -= 5; if (i&2) sum += 6; else sum -= 6; if (i&4) sum += 8; else sum -= 8; if (i&8) sum += 9; else sum -= 9; if (i&16) sum += 10; else sum -= 10; cout << i << " " << sum << endl; }
9
9
It is: 3+6 = 9
It is: 6+9 = 15
The sum of 9 and -6 is 3.
3 and 6
The number is 54. The sum of its digits is 5 + 4 = 9. 54/9 = 6.