127+20 =147.
It is: 127+39+262 = 428
The gap is 127.
In the problem 56 + 28 = 84, 84 is the sum.
If we use numbers that can be written with only ones and zeros, then we're working with binary numbers. The largest binary number that can be written with seven bits is "127". When you remember to include 'zero', that makes a total of 128 different numbers. The sum of the (smallest + largest) is (0 + 127) = 127 The sum of the (second smallest + second largest) = (1 + 126) = 127 The sum of the (third smallest + third largest) = (2 + 125) = 127 Each sum built in this way is 127, and there are (half of 128) = 64 of them. So the sum of all 128 numbers is (64 times 127) = 8,128
56 + 64 = 120
243+56 = 299
56 + 9 = 65
The wrong answer.
The two numbers with the sum of 15 and the product of 56 are: 7 + 8 = 15 7 x 8 = 56
-52
The sum of 24 and 32 is 56.