Let's denote the three consecutive odd integers as x, x+2, and x+4. Since they are odd integers, they are separated by 2 units. The sum of these integers can be represented as x + (x+2) + (x+4) = 3x + 6. Given that the sum is -72, we can set up the equation 3x + 6 = -72 and solve for x. Subtracting 6 from both sides, we get 3x = -78. Dividing by 3, we find x = -26. Therefore, the sum of the three consecutive odd integers is -72.
20,21 and 22 are three consecutive integers whose sum is 63. 20+21+22
22.
The integers are 21, 22, 23 and 24.
They are 21 and 22
26
Let's denote the three consecutive odd integers as x, x+2, and x+4. Since they are odd integers, they are separated by 2 units. The sum of these integers can be represented as x + (x+2) + (x+4) = 3x + 6. Given that the sum is -72, we can set up the equation 3x + 6 = -72 and solve for x. Subtracting 6 from both sides, we get 3x = -78. Dividing by 3, we find x = -26. Therefore, the sum of the three consecutive odd integers is -72.
20,21 and 22 are three consecutive integers whose sum is 63. 20+21+22
43 is the sum of the two consecutive integers 21 and 22.
22.
The integers are 21, 22, 23 and 24.
They are 21 and 22
The numbers are -22, -21 and -20.
The integers are 20 and 22.
There are 22 integers between them.
21, 22, 23
22, 23, 24 and 25.