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The sum of two consecutive even integers is -134. Find the numbers?
-66 and -68
The sum of three consecutive numbers is 66 what are the numbers?
21,22,23 21,22,23
What are three consecutive numbers that sum to 201?
66 + 67 + 68
Find 2 consecutive even integers whose sum is 66?
Two identical integers whose sum is 66 are 33 and 33. Add 1 and subtract 1. Now you have 32 and 34. Voilà : two consecutive even integers whose sum is 66.**************************************************************My answer here is the same as the answer above, I'm just going to explain in detail how to actually solve a problem like this. Two consecutive even integers would be like 2 and 4 or 632 and 634. See how the numbers come right after each other, that would be a consecutive integer. Since you wanted consecutive even integers, they are 2 even numbers that come after each other. Now, to solve your problem, the 'formula' for finding 2 consecutive even (and odd, plain consecutive integers would be different) integers for the sum of 66 would be:x + x+2 = 66. First, you add like terms. What I mean, is that you add all your x values and all your normal numbers, which gets us:2x + 2 = 66 Now, you have a normal 2-step equation. To solve a 2-step equation, first you tik-tok. This means if you have any subtraction, you change it so that you add negatives instead(none here). For example 6x-3 changes into 6x + -3. Then you add like terms, which I already explained somewhere above (none here). Then, you add the opposite of your lonesome number(number without a variable) to both sides of the equation. So for example here, you add -2 to both sides of the equation so that you can get rid of that lonesome number, like here:2x + (2 + -2)=66 + -2 -----> 2x = 64 ( no need to put + 0) Now all you have left to do is divide both sides of the equation by the coefficient of the x term, here being 2. LOOK TO SEE IF IT's POSITIVE OR NEGATIVE!!!!:2x = 64-------- X=32 So if your original equation was x + x+2 = 66, you just2 2plug in the numbers in the equation. So:x=32, 32+ 32+2 = 66 -----> 32+34=66 ------> Your 2 consecutive numbers are 32 and 34. Hope I helped. I know it's a looong answer, but I like things to be explained :-)
What two numbers consecutively sum 131?
The numbers are 65 and 66.
What are four consecutive integers with the sum of -66?
Let's denote the four consecutive integers as n, n+1, n+2, and n+3. The sum of these integers can be represented as n + (n+1) + (n+2) + (n+3) = 4n + 6. Given that the sum is -66, we can set up the equation 4n + 6 = -66. Solving for n, we find that n = -18. Therefore, the four consecutive integers are -18, -17, -16, and -15.
Find four consecutive integers such that the sum of the second and fourth is 132?
64 65 66 67
What are four consecutive integers whose sum is 66?
The numbers are -18, -17, -16 and -15.
What are three consecutive numbers that add up to 66?
The average of three numbers which sum to 66 is 66/3 = 22. If 22 is the sum of three consecutive integers, then those three integers are 21,22,23. Kermit Rose
What are consecutive integers with a sum of -66?
The numbers are -23, -22, and -21.
The sum of 3 consecutive even integers is -198 what are the integers?
201
What is the sum of two consecutive integers that equals 66?
It's an imaginary number, one that exists only in fiction, if the author wants it to. There are no two consecutive integers whose sum is 66. 32 + 33 = 65 33 + 34 = 67 The sum of two consecutive integers is always an odd number.
What 3 consecutive integers have a sum of 66?
The numbers are 21, 22 and 23.
What is the sum of three even consecutive integers is 198?
65, 66, 67
What are three consecutive integers whose sum is 195?
They are 64, 65 and 66 as well as a set of consecutive odd integers: 63, 65 and 67.
The sum of two consecutive even integers is -134. Find the numbers?
-66 and -68
What 3 consecutive integers whose sum is -63?
66
