What is the surface area of 45 gallons?

Answer 1

The surface area depends upon the shape of the volume of 45 gallons. The minimum is a sphere:

volume_sphere = ⁴/₃ × π × radius³

→ radius = ∛(³/₄ × volume_sphere ÷ π) = (³/₄ × volume_sphere ÷ π)^⅓

surface_area = 4 × π × radius²

→ surface_area = 4 × π × (³/₄ × volume_sphere ÷ π)^⅔

1 US gallon ≈ 0.161 cu ft

→ 45 US gallon ≈ 7.22 cu ft

→ minimum_surface_area ≈ 4 × π × (³/₄ × 7.22 cu ft ÷ π)^⅔

≈ 18.07 sq ft.

Therefore the surface area of 45 US gallons is greater than or equal to approx 18.07 sq ft.

1 imp gallon ≈ 0.00455 cu m

→ 45 imp gallon ≈ 0.205 cu m

→ minimum_surface_area ≈ 4 × π × (³/₄ × 0.203 m³ ÷ π)^⅔

≈ 1.679 m²

Therefore the surface area of 45 imperial gallons is greater than or equal to approx 1.679 m².

Answer 2

None, since there can be no conversion. A surface is a measure of area in 2-dimensional space while a gallon is a measure of volume in 3-dimensional space. The two measure different characteristics and, according to the most basic principles of dimensional analysis, any attempt at comparisons or conversions between the two are fundamentally flawed.

Answer 3

You can't calculate the surface are based on the volume. It could be almost anything, depending on the shape of the object.