It depends on wat n is like if it was 3 then the answer is 13
√(-10 - 5n2 - 330) = i√(5n2 + 340) = i√[(5(n2 + 68)]
5n2 + 17n + 6 is a quadratic expression. It can be factorised as 5n2 + 17n + 6 = (5n + 2)(n + 3). The expression can be expressed as equal to to a fixed or variable amount when it becomes a function of n. Example : 5n2 + 17n + 6 = 7 or y = 5n2 + 17n + 6
5 * * * * * No. It should be 5n2
(5n + 1)(n + 7)
-4n3 + 8n2 - 4n + 7
√(-10 - 5n2 - 330) = i√(5n2 + 340) = i√[(5(n2 + 68)]
5n2 + 17n + 6 is a quadratic expression. It can be factorised as 5n2 + 17n + 6 = (5n + 2)(n + 3). The expression can be expressed as equal to to a fixed or variable amount when it becomes a function of n. Example : 5n2 + 17n + 6 = 7 or y = 5n2 + 17n + 6
5 * * * * * No. It should be 5n2
(5n + 1)(n + 7)
5(n2 + 2n + 4)
CH=CH + 5N2O -----> 5N2 + 2CO2 + H2O
-4n3 + 8n2 - 4n + 7
4NH3 + 6NO -> 5N2 + 6H2O 145 g N2 x (1 mol/28.0 g) x (6 mol NO/5 mol N2) x (30.0 g NO/1 mol NO) = 186.4285714 g NO rounds to 186 g NO due to significant figures
86. Generated by the cubic t(n) = n3 - 5n2 + 9n - 4 for n = 1, 2, 3, ...
Take 5 out. If the missing signs are pluses, it becomes 5(n2 + 2n + 4) If the missing signs are minuses, it becomes 5(n2 - 2n - 4)
Given any number, it is always possible to find a polynomial of degree 6 that will fit the above numbers and the additional given number.The simplest position to value rule, in polynomial form, for the above sequence isUn = (3n3 - 5n2 + 4n - 12)/2 for n = 1, 2, 3, ...and accordingly, U7 = 412.
There are infinitely many rules that can generate this sequence. As imple one is Un = 5n2 - 21n +72 for n = 1, 2, 3, ... And then n = 4 gives U4 = 68