7
√(-10 - 5n2 - 330) = i√(5n2 + 340) = i√[(5(n2 + 68)]
5n2 + 17n + 6 is a quadratic expression. It can be factorised as 5n2 + 17n + 6 = (5n + 2)(n + 3). The expression can be expressed as equal to to a fixed or variable amount when it becomes a function of n. Example : 5n2 + 17n + 6 = 7 or y = 5n2 + 17n + 6
5 * * * * * No. It should be 5n2
(5n + 1)(n + 7)
-4n3 + 8n2 - 4n + 7
√(-10 - 5n2 - 330) = i√(5n2 + 340) = i√[(5(n2 + 68)]
5n2 + 17n + 6 is a quadratic expression. It can be factorised as 5n2 + 17n + 6 = (5n + 2)(n + 3). The expression can be expressed as equal to to a fixed or variable amount when it becomes a function of n. Example : 5n2 + 17n + 6 = 7 or y = 5n2 + 17n + 6
5 * * * * * No. It should be 5n2
(5n + 1)(n + 7)
5(n2 + 2n + 4)
-4n3 + 8n2 - 4n + 7
86. Generated by the cubic t(n) = n3 - 5n2 + 9n - 4 for n = 1, 2, 3, ...
Take 5 out. If the missing signs are pluses, it becomes 5(n2 + 2n + 4) If the missing signs are minuses, it becomes 5(n2 - 2n - 4)
The reaction equation for the oxidation of acetylene (C2H2) with nitrous oxide (N2O) is: 2C2H2 + N2O -> 2CO2 + H2O + N2
Given any number, it is always possible to find a polynomial of degree 6 that will fit the above numbers and the additional given number.The simplest position to value rule, in polynomial form, for the above sequence isUn = (3n3 - 5n2 + 4n - 12)/2 for n = 1, 2, 3, ...and accordingly, U7 = 412.
There are infinitely many rules that can generate this sequence. As imple one is Un = 5n2 - 21n +72 for n = 1, 2, 3, ... And then n = 4 gives U4 = 68
The expression "5n^2 + 31n - 72" is a quadratic polynomial in terms of the variable ( n ). It can be analyzed using methods such as factoring, completing the square, or applying the quadratic formula to find its roots. If you need specific information about its properties or solutions, please clarify!