" 3x + 5 " does.
3x - y = -4 3x - y = 0 Those lines do not intersect. They are parallel. You can demonstrate by solving either of them for one of the two variables, then plugging it's value into the other: 3x - y = -4 ∴y = 3x + 4 Now substitute: 3x - y = 0 ∴ 3x - (3x + 4) = 0 ∴ 3x - 3x - 4 = 0 ∴ -4 = 0 This result is obviously incorrect, indicating that the lines do not intersect.
7
-(3x-4) = -3x + 4
y=3x+4 -3x+y=4 x=-1/3
7
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
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3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
3x - y = 4 Get y by itself to see if it is the same as y = 3x - 4: 3x = 4 + y 3x - 4 = y Therefore, 3x - y = 4 is the equivalent of y = 3x - 4.
3x+4y = 17 -3x -3x 4y = -3x+17 Divide each TERM by 4 y = -3x + 17 4 4
2x
2x
3x+4y = 17 -3x -3x 4y = -3x+17 Divide each TERM by 4 y = -3x + 17 4 4
-3x+14 = -4 -3x = -4-14 -3x = -18 x = 6
" 3x + 5 " does.
Solve:4 - 3x = 104 - 3x - 4 = 10 - 4-3x = 6-3x/-3 = 6/-3x = -2Check:4 - (3 x -2) = 104 - (-6) = 104 + 6 = 1010 = 10