That completely depends on what number 'x' is. And it changes immediately
if 'x' changes.
Maybe you were told to "factor" [ x2-2x ], and while trying to get the answer
from somewhere else, failed even to repeat the question accurately. We see
that quite often around here.
That expression can be factored and written as [ x(x-2) ].
That doesn't change its value in any way. It's just a different way to write
the same exact thing.
Derivation of x2 or 2x is 2.
What do you want to convert it to? x2 + y2 = 2x If you want to solve for y: x2 + y2 = 2x ∴ y2 = 2x - x2 ∴ y = (2x - x2)1/2 If you want to solve for x: x2 + y2 = 2x ∴ x2 - 2x = -y2 ∴ x2 - 2x + 1 = 1 - y2 ∴ (x - 1)2 = 1 - y2 ∴ x - 1 = ±(1 - y2)1/2 ∴ x = 1 ± (1 - y2)1/2
2x = x2 + 4x - 3 x2 + 2x - 3 = 0 (x - 1)(x - 2) = 0
x3 - x2 + 2x = x*(x2 - x + 2) which cannot be factored further.
x2 + 2x - 15 = (x - 3)(x + 5)
x2+2x-15
x2 × 2x = 2x3
Derivation of x2 or 2x is 2.
x2+2x-63 = (x-7)(x+9) when factored
What do you want to convert it to? x2 + y2 = 2x If you want to solve for y: x2 + y2 = 2x ∴ y2 = 2x - x2 ∴ y = (2x - x2)1/2 If you want to solve for x: x2 + y2 = 2x ∴ x2 - 2x = -y2 ∴ x2 - 2x + 1 = 1 - y2 ∴ (x - 1)2 = 1 - y2 ∴ x - 1 = ±(1 - y2)1/2 ∴ x = 1 ± (1 - y2)1/2
2x = x2 + 4x - 3 x2 + 2x - 3 = 0 (x - 1)(x - 2) = 0
The antiderivative of 2x is x2.
x2 + 2x - 3 = (x + 3)(x - 1)
x3 - x2 + 2x = x*(x2 - x + 2) which cannot be factored further.
negative four: x2 - 2x + 5 = x2 - 2x + 5 - 4 = x2 - 2x + 1 = (x - 1)2
If you mean x2 + 2x + 15: Then the answer would be that it's a quadratic expression with no factors. If you mean x2 - 2x + 15: Then it can be factored out to: (x - 5)(x + 3) If you mean x2 + 2x - 15: Then it can be factored out to: (x + 5)(x - 3)
x2 + 2x - 15 = (x - 3)(x + 5)