x^2+2x+40 = x^2-x+190Subtract x^2 from both sides2x+40 = -x+190Add x to both sides3x + 40 = 190Subtract 40 from each side3x = 150Divide both sides by 3x = 50
10 + x = 50x = 40
x2+14x+40 = (x+4)(x+10) when factored
x=34
10x plus 40 is 50x.10+40=50 and then you just add the x so:10x+40=50x
If 40 plus x equals 25 then x is equal to -15.
x + 3x = 40 4x = 40 x = 10.
x2 + 13x + 40 = x2 + 5x + 8x + 40 = x(x + 5) + 8(x + 5) = (x + 8)(x + 5)
40 + (40 x 0) + 1 = 41.
x^2+2x+40 = x^2-x+190Subtract x^2 from both sides2x+40 = -x+190Add x to both sides3x + 40 = 190Subtract 40 from each side3x = 150Divide both sides by 3x = 50
(x + 5)(x + 8)
10 + x = 50x = 40
x2+14x+40 = (x+4)(x+10) when factored
40 + 60 = 60 + x Addition has a property called the Commutative property which says that: x + y = y + x. So, over here: x = 40 y = 60 Thus, 40 + 60 = 60 + 40
x=34
x = 45
You can find the value of x by equating the two equations.x^2+2x+40 = x^2-x +190Firstly, subtract x^2 from both sides2x+40 = -x + 190Now subtract 40 from each side2x = -x + 150Now add x to each side3x = 150Divide by 3x = 50