xe^(5x) is an expression involving x and Euler's constant
5x^2(x^2 + 5)
To multiply (5x) by (x^2), you multiply the coefficients and add the exponents of the variables. The coefficient is 5, and the exponent of (x) in (5x) is 1. So, (5x \times x^2 = 5x^{1+2} = 5x^3).
The degree of a monomial is the sum of the exponents of its variables. In the monomial (-5x^{10}y^{3}), the exponent of (x) is 10 and the exponent of (y) is 3. Adding these together gives (10 + 3 = 13). Therefore, the degree of the monomial (-5x^{10}y^{3}) is 13.
To find the degree of the polynomial ( 7x^7 + 10x^4 + 4x^3 - 5x^{11} - 10x^6 - 6x^7 ), we identify the term with the highest exponent. The terms are ( 7x^7 ), ( 10x^4 ), ( 4x^3 ), ( -5x^{11} ), ( -10x^6 ), and ( -6x^7 ). The term with the highest exponent is ( -5x^{11} ), which has a degree of 11. Therefore, the degree of the polynomial is 11.
Am I right :P?5x^(3)-3x+4-3x^(3)-2x+6x-1Since 5x^(3) and -3x^(3) are like terms, add -3x^(3) to 5x^(3) to get 2x^(3).(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-3x+4-2x+6x-1Since -3x and -2x are like terms, subtract 2x from -3x to get -5x.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-5x+4+6x-1Since -5x and 6x are like terms, subtract 6x from -5x to get x.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+4-1Subtract 1 from 4 to get 3.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+3To find the derivative of 2x^(3), multiply the base (x) by the exponent (3), then subtract 1 from the exponent.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+(d)/(dx) x+3To find the derivative of x, multiply the base (x) by the exponent (1), then subtract 1 from the exponent (1-1=0). Since the exponent is now 0, x is eliminated from the term.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+(d)/(dx) 3Since 3 does not contain x, the derivative of 3 is 0.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+0Add 0 to 1 to get 1.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1The derivative of 5x^(3)-3x+4-3x^(3)-2x+6x-1 is 6x^(2)+1.6x^(2)+1
5x^2(x^2 + 5)
To multiply (5x) by (x^2), you multiply the coefficients and add the exponents of the variables. The coefficient is 5, and the exponent of (x) in (5x) is 1. So, (5x \times x^2 = 5x^{1+2} = 5x^3).
The degree is the term with the greatest exponent So in 3x^2 + 5x + 7 The degree is 2 since the highest exponent is 2 If there is no power sign assume that the number is to the 1 power 3x^2 + 5x + 7 can also be written as 3x^2 + 5x^1 + 7^1 ^ = power of
Well, isn't that a lovely little math problem we have here! To find the exponential form of -5x-5x-5x-5, we can simplify it by adding the exponents together. This gives us -5x^4, which is the exponential form of the expression you provided. Just remember, mistakes are just happy little accidents in the world of math!
8 times(2x2 - 5x - 3) = 8(2x + 1)(x - 3)
To differentiate the function f(x) 3x3 - 2x2 5x - 1 without being a d3x dt3, you can use the power rule for differentiation. This involves multiplying the coefficient of each term by the exponent of x and then decreasing the exponent by 1.
To find the degree of the polynomial ( 7x^7 + 10x^4 + 4x^3 - 5x^{11} - 10x^6 - 6x^7 ), we identify the term with the highest exponent. The terms are ( 7x^7 ), ( 10x^4 ), ( 4x^3 ), ( -5x^{11} ), ( -10x^6 ), and ( -6x^7 ). The term with the highest exponent is ( -5x^{11} ), which has a degree of 11. Therefore, the degree of the polynomial is 11.
Xenon has nine naturally occurring isotopes: Xe-124, Xe-126, Xe-128, Xe-129, Xe-130, Xe-131, Xe-132, Xe-134, and Xe-136.
You cannot ad or subtract variables with different exponents: the exponents must be the same. The coefficients are added or subtracted and the exponent of the answer is the common exponent. (The rules are similar to those for the denominators of fractions.)Thus 2x^2 + 5x^3 cannot be combined into a single term.while 2x^2 + 5x^2 = (2+5)*x^2 = 7x^2
Am I right :P?5x^(3)-3x+4-3x^(3)-2x+6x-1Since 5x^(3) and -3x^(3) are like terms, add -3x^(3) to 5x^(3) to get 2x^(3).(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-3x+4-2x+6x-1Since -3x and -2x are like terms, subtract 2x from -3x to get -5x.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-5x+4+6x-1Since -5x and 6x are like terms, subtract 6x from -5x to get x.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+4-1Subtract 1 from 4 to get 3.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+3To find the derivative of 2x^(3), multiply the base (x) by the exponent (3), then subtract 1 from the exponent.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+(d)/(dx) x+3To find the derivative of x, multiply the base (x) by the exponent (1), then subtract 1 from the exponent (1-1=0). Since the exponent is now 0, x is eliminated from the term.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+(d)/(dx) 3Since 3 does not contain x, the derivative of 3 is 0.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+0Add 0 to 1 to get 1.(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1The derivative of 5x^(3)-3x+4-3x^(3)-2x+6x-1 is 6x^(2)+1.6x^(2)+1
The derivative of xe is e. The derivative of xe is exe-1.
The exponent.