5x^2(x^2 + 5)
15
(5x - i)(5x + i) where i is the imaginary unit equivalent to the square root of negative one.
(5x - i)(5x + i) where i is the imaginary unit equivalent to the square root of negative one.
By splitting the Middle Term, 5X2 + 25X + 4X +20 5X(X+5) + 4(X+5) (5X+4)(X+5)
To factorise the expression (25x + 15y), first identify the greatest common factor (GCF) of the coefficients 25 and 15, which is 5. Then, factor out the GCF from the expression: [ 25x + 15y = 5(5x + 3y) ] So, the factored form is (5(5x + 3y)).
The GCF is 5x
15
35
(5x - i)(5x + i) where i is the imaginary unit equivalent to the square root of negative one.
(5x - i)(5x + i) where i is the imaginary unit equivalent to the square root of negative one.
30x2+25x-24x-20 = 30x2+x-20 = (6x+5)(5x-4) when factored
(5x - 2y)(5x + 2y)
25x'2
It's a square factor.25x2-36.5x*5x 6*6Answer: (5x-6)(5x+6)
By splitting the Middle Term, 5X2 + 25X + 4X +20 5X(X+5) + 4(X+5) (5X+4)(X+5)
I assume you mean 10x - 25x^2 (i.e. to the power of 2, or x squared) If so 10x - 25x^2 = 5x (2 - 5x)
(5x + y)(25x^2 - 5xy + y^2)