1700 = 2 x 2 x 5 x 5 x 17. This is one possibility. There are several more:
Notice how I have grouped the smaller factors together with the parentheses to make bigger factors. I could equally well have grouped three numbers together or even four. I could also have shuffled the numbers around to make different combinations.
1700 = MDCC (1000+500+100+100 = 1700) 5000 = (V) or V but with an horizontal above the numeral Numerals in brackets or with an horizontal bar above them indicate multiplication by a thousand. (V) = 5*1000 = 5000
6x2x2
How about: 8*9 = 72
The number 39 can be expressed as a multiplication problem using the factors 3 and 13, since (3 \times 13 = 39). Additionally, it can also be represented as (1 \times 39) or (39 \times 1). These factors demonstrate the different ways to compose the number 39 through multiplication.
3 times 35 equals 105
1700 = MDCC (1000+500+100+100 = 1700) 5000 = (V) or V but with an horizontal above the numeral Numerals in brackets or with an horizontal bar above them indicate multiplication by a thousand. (V) = 5*1000 = 5000
6x2x2
How about: 8*9 = 72
37 x 2
You multiply it and your finding space of what it has. The multiplication makes the squared.
3 times 35 equals 105
They are: 3*7 = 21 or 1*21 = 21
1 x 38, 2 x 19.
1 x 293, 293 x 1.
As a product of its prime factors: 333*5 = 135
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It is: 1 times 23 = 23 which is a prime number