Any multiple of 315.
9
9 is the composite number. the factors are: 1,3 and 9. all the rest are prime.
7 and 9 are both divisible by one. 7 and 9 are both prime numbers, meaning the factors are 1 and themselves. The factors of 7 are 1 and 7. The factors of 9 are 1 and 9.
The number that can be decomposed into (3 \times 3 \times 5 \times 7) is 315. This is calculated by multiplying the factors together: (3 \times 3 = 9), then (9 \times 5 = 45), and finally (45 \times 7 = 315). Thus, the product of these factors equals 315.
0
5 and 7 are prime numbers. and 3 goes into 9, so the only number that goes into 5, 7, and 9 is 1. They are what we call "relatively prime", even though 9 is not prime, because they have no common factors other than 1.
9
9 is the composite number. the factors are: 1,3 and 9. all the rest are prime.
5 is a prime number and has no factors other than 1 and 5. Factors of 9 are 1, 3, 9. 5 and 9 have no common factors other than 1.
2520 is one.
7 and 9 are both divisible by one. 7 and 9 are both prime numbers, meaning the factors are 1 and themselves. The factors of 7 are 1 and 7. The factors of 9 are 1 and 9.
441
52 over 9 as a mixed number is: 52/9 = 45/9 + 7/9 = 5 7/9
To find the smallest number that has 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 as factors, you need to find the least common multiple (LCM) of these numbers. The LCM is the smallest number that is divisible by all the given numbers. The LCM of 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 is 2520. Therefore, 2520 is the smallest number that has 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10 as factors.
The number that can be decomposed into (3 \times 3 \times 5 \times 7) is 315. This is calculated by multiplying the factors together: (3 \times 3 = 9), then (9 \times 5 = 45), and finally (45 \times 7 = 315). Thus, the product of these factors equals 315.
126
45