For a number to be divisible by another number it must be at least that number. As 3 is less than 605 it cannot be divisible by 605. Also 3 is not a FACTOR of 605, that is 3 does not divide into 605 without remainder.
No, 19 is not divisible by 3. When a number is divisible by another number, it means that the division results in a whole number without any remainder. In this case, when you divide 19 by 3, the result is 6 with a remainder of 1, indicating that 19 is not evenly divisible by 3.
If the sum of the digits of a number is divisible by 3 ,then the number is divisible by 3.. is 36 is right
For a number to be divisible by another number it must be at least that number. As 3 is less than 837 it cannot be divisible by 837. However, 3 IS a FACTOR of 837, that is 3 divides into 837 without remainder.
Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.
A number divided by 2 its reminder is 1, A number divided by 3 its reminder is 2, A number divided by 4 its reminder is 3, A number divided by 5 its reminder is 4, A number divided by 6 its reminder is 5, A number divided by 7 its reminder is 6, A number divided by 8 its reminder is 7, A number divided by 9 its reminder is 8, A number divided by 10 its reminder is 9 what is that number?
For a number to be divisible by another number it must be at least that number. As 3 is less than 605 it cannot be divisible by 605. Also 3 is not a FACTOR of 605, that is 3 does not divide into 605 without remainder.
To know if a number is composite without listing its factors, you can use these rules:All numbers that end with 2, 4, 6, 8, and 0 (even numbers) are divisible by 2.If the sum of the digits in a number is divisible by 3, the number is divisible by 3.If the last two digits are divisible by 4, the number is divisible by 4.All numbers that have 5 in the one's place are divisible by 5.If a number is divisible by 2 AND is divisible by 3, it is divisible by 6.If the last 3 digits of a number are divisible by 8, the number is divisible by 8.If the sum of the digits of number is divisible by 9, the number is divisible by 9.If a number ends wuth 0, the number is divisible by 10.
If you can divide a number by three without a remainder, the number is said to be divisible by 3.
Converse:If a number is divisible by 3, then every number of a digit is divisible by three. Inverse: If every digit of a number is not divisible by 3 then the number is not divisible by 3? Contrapositive:If a number is not divisible by 3, then every number of a digit is not divisible by three.
35 is not divisible by 3.
No, 19 is not divisible by 3. When a number is divisible by another number, it means that the division results in a whole number without any remainder. In this case, when you divide 19 by 3, the result is 6 with a remainder of 1, indicating that 19 is not evenly divisible by 3.
If the sum of the digits of a number is divisible by 3, then the number is divisible by 3.
There is no such number. Since 6 is divisible by 3, then any number that is divisible by 6 automatically has to be divisible by 3.
A number is divisible by 3 if the sum of its digits is divisible by 3.
No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.
I think the question is mistyped, and should be "Is 414 evenly divisible by 3?" i.e. does it divide by 3 without leaving a remainder. The answer is yes. A quick way to tell if a number is divisible by 3 is to add the digits and if the total is divisible by 3, then the number in question is also divisible by 3 4 + 1 + 4 = 9 and 9 is divisible by 3 414 ÷ 3 = 138