7 is a Prime number, so integers can't be multiplied to make 7. It can't be divided ether (unless by 1 or itself)
Coprime numbers are those in which only 1 and that number (say 5) can be divisible by it. Both 5 and 7 would be coprime numbers because they are numbers divisible by only themselves and 1.
There are 282 such numbers.
No, the number 1155 is divisible by four prime numbers (3, 5, 7, 11).
14. Assuming dealing with only counting numbers (ie integers greater than 0): Numbers divisible by 5 or 7 are their multiples. 50 ÷ 5 = 10 → last multiple of 5 less than 50 is 9 x 5 → 9 numbers less than 50 are divisible by 5 50 ÷ 7 = 71/7 → last multiple of 7 less than 50 is 7 x 7 → 7 numbers less than 50 are divisible by 7 Numbers divisible by both are those which are multiples of their lowest common multiple = 35 50 ÷ 35 = 115/35 → last multiple of 35 less than 50 is 1 x 35 → 1 number less than 50 is divisible by both 5 and 7 and needs to be removed from both the above counts. → (9 - 1) + (7 - 1) = 14 numbers less than 50 are divisible by 5 or 7 but not both. If there is no restriction on numbers being greater than 0, there are infinitely many numbers as it includes the infinite number of negative numbers which are all less than 50 and provide an infinite number of numbers divisible by 5 or 7 but not both.
1,3,5,7,9 Odd numbers are the ones that if you repeatedly subtract 2 from, you will end with 1. Odd numbers always end in 1, 3, 5,7, and 9. Examples: 23, 37, 51, 69, 75, 87, 99
Coprime numbers are those in which only 1 and that number (say 5) can be divisible by it. Both 5 and 7 would be coprime numbers because they are numbers divisible by only themselves and 1.
There are 282 such numbers.
35 and all its multiples.
No, the number 1155 is divisible by four prime numbers (3, 5, 7, 11).
NO. Odd numbers are not always divisible by 5. Examples: 3 , 7, 9, 11, 13, 17, ... are odd numbers and they are not divisible by 5.
Oh, dude, let's break it down. So, first, you gotta figure out how many numbers are divisible by 3, right? Then, do the same for 7. But, here's the kicker - you gotta remember to subtract the numbers divisible by both 3 and 7. It's like a math puzzle, but with numbers. So, like, get your calculator out and have fun with it.
5, 7, a bunch of numbers that are odd are not divisible by 3. numbers that are divisible by three can have all their numbers added together and come out with a number that is divisible by 3.
14. Assuming dealing with only counting numbers (ie integers greater than 0): Numbers divisible by 5 or 7 are their multiples. 50 ÷ 5 = 10 → last multiple of 5 less than 50 is 9 x 5 → 9 numbers less than 50 are divisible by 5 50 ÷ 7 = 71/7 → last multiple of 7 less than 50 is 7 x 7 → 7 numbers less than 50 are divisible by 7 Numbers divisible by both are those which are multiples of their lowest common multiple = 35 50 ÷ 35 = 115/35 → last multiple of 35 less than 50 is 1 x 35 → 1 number less than 50 is divisible by both 5 and 7 and needs to be removed from both the above counts. → (9 - 1) + (7 - 1) = 14 numbers less than 50 are divisible by 5 or 7 but not both. If there is no restriction on numbers being greater than 0, there are infinitely many numbers as it includes the infinite number of negative numbers which are all less than 50 and provide an infinite number of numbers divisible by 5 or 7 but not both.
1,3,5,7,9 Odd numbers are the ones that if you repeatedly subtract 2 from, you will end with 1. Odd numbers always end in 1, 3, 5,7, and 9. Examples: 23, 37, 51, 69, 75, 87, 99
There are many number that are divisible by 5, but not 7. Some are 10, 15, 20, 25, 30, 40, 45, 50, 55, 60, etc. 35 was not listed because it is divisible by 5 and 7.
no 7 + 6 + 7 = 20 = 2 + 0 = 2 numbers divisible by 9 add up to 9 85.2222 = 767 / 9
1, 2, 4, 5, 7, 8