They are the numbers that when divided by 2 leave a remainder of 1
This is an extremely poor question. There are 28 pairs of numbers and, in less than 10 minutes, I could find reasons why 17 pair were different from the other numbers in the set. A bit more time and I am sure I could do the rest. So here they are: 53 and 72: leave a remainder of 15 when divided by 19. 53 and 77: leave a remainder of 5 when divided by 12. 53 and 82: leave a remainder of 24 when divided by 29. 53 and 87: leave a remainder of 2 when divided by 17. 53 and 95: leave a remainder of 11 when divided by 21. 53 and 97: leave a remainder of 9 when divided by 11. 67 and 95: leave a remainder of 11 when divided by 28. 67 and 87: leave a remainder of 7 when divided by 17. 67 and 97: leave a remainder of 7 when divided by 30. 72 and 82: leave a remainder of 0 when divided by 2 (are even). 72 and 87: leave a remainder of 0 when divided by 3 (multiples of 3). 72 and 95: leave a remainder of 3 when divided by 23. 72 and 97: leave a remainder of 22 when divided by 25. 77 and 95: leave a remainder of 5 when divided by 9. 77 and 97: leave a remainder of 17 when divided by 20. 82 and 95: leave a remainder of 4 when divided by 13. 87 and 95: leave a remainder of 7 when divided by 8.
It is: 4710 which will leave no remainder when divided by 2 or 3
It is 98910.
It can be defined as the set of all integers that leave a remainder of 1 when divided by 2.
Even numbers are multiples of 2. They end in 0, 2, 4, 6 or 8.Anything ending in 0, 2, 4, 6 or 8.
It is an Odd number. Even numbers are those which have no remainder when divided by 2.
1, 2, 3, 5, 6, 10, 15 and 30.
Integers that are divisible by 3, integers that leave a remainder of 1 when divided by 3 and integers that leave a remainder of 2 when divided by 3.
11 different numbers leave a remainder of 1 when divided into 61.
Odd numbers can't be evenly divided by 2 because there will always be a remainder of 1
All of them. Only 4 does not leave a remainder of 1.