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A straight line, passing through the point (0,5) with a gradient of -3.
No, the two lines are not perpendicular.
It is a straight line equation and can be rearranged in the form of:- y = -3x+5
When the equation of a line is written in standard form: y = mx + c, the slope of the line is m. Here, y = 3x + 5 so slope = 3
y-6=3x-5 y=3x+1 (0,1)(1,4)(2,7)etc
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If you mean the perpendicular distance from the coordinate of (7, 5) to the straight line 3x+4y-16 = 0 then it works out as 5 units.
A straight line, passing through the point (0,5) with a gradient of -3.
No, the two lines are not perpendicular.
It is a straight line equation and can be rearranged in the form of:- y = -3x+5
3X + 5Y = 155Y = -3X + 15Y = (-3/5)X + 3The slope of this line is -3/5.The slope of a line perpendicular to it is 5/3.
5, of course!
When the equation of a line is written in standard form: y = mx + c, the slope of the line is m. Here, y = 3x + 5 so slope = 3
y = 3x+5 is parallel to y = 3x+7
The parallel equation works out as: 4y = 3x+1 which can be expressed in the form of 3x-4y+1 = 0
4