y = 3x+5 is parallel to y = 3x+7
This is simple algebra. You should know that parallel lines have the same slope. So you would take the slope of the line that is given to you and set it up in the equation y= mx + b. m stand for your slope and you would take the point that it gives you (3, -1) and plug it into y = mx + b (along with your slope) and solve for b..once you've solved for b, you can set up your equation because you know your slope (m) and y-intercept (b). If you are having trouble finding the slope, just solve the equation for y. Get y on one side of the equation. The number that is with x will be your slope. Good luck!
A kite would fit the given description
The locus of points at a given distance to a line would be a line parallel to the first line. Assuming that both lines are straight.
no, if they are both in the same plane and IF EXTENDED INDEFINITELY would never intersect at any point then the segments are considered parallel.
Yes. 6y = 18x can be cancelled down to y = 3x. If drawn on a graph, the gradient of the straight line at any given point would be 3. The line also crosses the point (0, 0) [the origin]
No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.
That of course would depend on the straight line equation that has not been given and so therefore an answer is not possible.
x = 1 (the line intersects the x-axis at 1, and is parallel to the y-axis)We cannot write the equation on the Slope-intercept form, since the slope of the line is undefined. 1 is the x-coordinate of any point on the given line.
All lines that have the same slope are parallel to each other. To determine which lines are parallel to the give equation, you must first have to determine the slope of the equation. Notice that your equation is written in y = mx + b form, where m represents slope. In this case, m = 2. Any equation with a slope of 2 is parallel to your given line. For examples of lines that would be parallel, the following are all parallel: y = 2x y = 2x + 1 y = 2x + 2 y = 2x + 100
This is simple algebra. You should know that parallel lines have the same slope. So you would take the slope of the line that is given to you and set it up in the equation y= mx + b. m stand for your slope and you would take the point that it gives you (3, -1) and plug it into y = mx + b (along with your slope) and solve for b..once you've solved for b, you can set up your equation because you know your slope (m) and y-intercept (b). If you are having trouble finding the slope, just solve the equation for y. Get y on one side of the equation. The number that is with x will be your slope. Good luck!
Slope Intercept form is meant for a line, so if you know the slope m in the equation y=mx+b then with a given point say (3,4) and say the slope of the line was 2 then the equation would read y=2x+4.
If you mean y = 2x-3 then the parallel equation will have the same slope of 2 but with a different y intercept
For a line to be parallel to the y-axis it must be a vertical line. therefore in order for the line to pass through the point (-1,5) you need to only be concerned with the x value of the point and your line would be x=-1.
They would 'intersect'. ('cross', have one point in common)
You would need a point ex: (4,5) y=5 if its a horizontal line you just write y=(value of y on the given point)
It would look like a straight vertical line, i.e. parallel to the y-axis, passing through the point on the x-axis where x=3.
In a 2 dimensional plain they would have to be parallel in order to have no common point; in a 3 dimensional field they do not have to be parallel.