23
To find two numbers that multiply to -132 and add to 2, we can set them as ( x ) and ( y ). The numbers that satisfy these conditions are 12 and -11, since ( 12 \times -11 = -132 ) and ( 12 + (-11) = 1 ). Therefore, the two numbers are 12 and -11.
The consecutive numbers that add up to 36 are 11, 12, and 13. When you add these three numbers together (11 + 12 + 13), the sum is 36.
The numbers are -12, -11, -10 and -9.
10+11+12
They are: 11 times 12 = 132
To find two numbers that multiply to -132 and add to 2, we can set them as ( x ) and ( y ). The numbers that satisfy these conditions are 12 and -11, since ( 12 \times -11 = -132 ) and ( 12 + (-11) = 1 ). Therefore, the two numbers are 12 and -11.
-11
The consecutive numbers that add up to 36 are 11, 12, and 13. When you add these three numbers together (11 + 12 + 13), the sum is 36.
12 and 1
The numbers are -12, -11, -10 and -9.
The numbers are -1 and -11 because -1 times -11 = 11 and (-1)+(-11) = -12
-23
10+11+12
23
They are: 11 times 12 = 132
11. Add all the numbers then divide by how many numbers there are.
The two prime numbers that add up to 19 are 7 and 12. Prime numbers are numbers greater than 1 that can only be divided by 1 and themselves. In this case, 7 and 12 are not prime numbers, and there are no two prime numbers that add up to 19.