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Immanuel Connelly

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3y ago
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13y ago

This can solved by forming quadratic equation.

Let one of the number be x, then other number = 2-x

Also, x(2-x) = -12 (Since product of the numbers is -12)

2x - x2 = -12

Multiplying both sides by -1

x2 - 2x = 12

x2 - 2x - 12 = 0

The equation is of the form: ax2+bx+c = 0

On comparing we get, a = 1, b = -2 and c = -12

Now, we will calculate D, D = b2 - 4ac = 4 - 4x1x(-12) = 52.

Now, x can be known by using the relation: x = (-b + D1/2)/2a or x = (-b - D1/2)/2a

Plugging in the values, we get

x = (2 + 2 X 131/2)/2 or x = (2 - 2 X 131/2)/2 (Here Bold X indicates multiply)

On further simplification we get:

x = 1+131/2 or x = 1-131/2

If one of the number is 1 + 131/2 then other is 1 - 131/2. (Since sum of the numbers is 2)

If one of the number is 1 - 131/2 then other is 1 + 131/2.

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Q: What two numbers add to positive 2 and multiply to negative 12?
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