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The two numbers that add to positive 2 and multiply to negative 12 are 6 and -2. This is because 6 + (-2) = 4 and 6 * (-2) = -12. In this case, the positive 6 and negative 2 satisfy both conditions simultaneously.
This can solved by forming quadratic equation.
Let one of the number be x, then other number = 2-x
Also, x(2-x) = -12 (Since product of the numbers is -12)
2x - x2 = -12
Multiplying both sides by -1
x2 - 2x = 12
x2 - 2x - 12 = 0
The equation is of the form: ax2+bx+c = 0
On comparing we get, a = 1, b = -2 and c = -12
Now, we will calculate D, D = b2 - 4ac = 4 - 4x1x(-12) = 52.
Now, x can be known by using the relation: x = (-b + D1/2)/2a or x = (-b - D1/2)/2a
Plugging in the values, we get
x = (2 + 2 X 131/2)/2 or x = (2 - 2 X 131/2)/2 (Here Bold X indicates multiply)
On further simplification we get:
x = 1+131/2 or x = 1-131/2
If one of the number is 1 + 131/2 then other is 1 - 131/2. (Since sum of the numbers is 2)
If one of the number is 1 - 131/2 then other is 1 + 131/2.
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136
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How do multiply a negative fraction time a positive fraction?
Multiply the numbers ignoring the signs and then add a negative sign.
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What is the sign for multiplication and addition?
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