If multiplying 3 digit numbers with 2 digit numbers. For example; 345 x 92= First you will start with 2 by multiplying it by 5 then carry the 1 above the 4 then multiply the "2" with 4 then add the number on-top of the 4 which is 1 and it will give you 9. 4 x 2= 8+1=9. Then times the 2 by 3 which is 6. That is not your answer, yet. 690 plus the amount you get by multiplying 9 by every number, 5 then carry the number, 4 times 9, plus the number above it, then carry the 3 on top of the 3. Then add your total to 690 or what ever your equation is.
Multiply the two numbers together as if there were no decimal places. But if there are any zeros at the end of the multiple don't get rid of them (yet). Count the number of digits after (to the right of) the decimal points in the two numbers. Add them together. That is the number of digits after the decimal that you want in the answer. So to calculate 1.25 * 3.4 125*34 = 4250 You have 2 digits after the decimal in 1.25 and 1 in 2.4 - a total of 3 So you need 3 digits after the decimal in the answer, which gives 4.250 You can THEN get rid of the trailing zero(s) and simplify to 4.25
Find out what two numbers add up to -8 yet when mutiplied they produce 12 and so: x squared-8x+12 = (x-2)(x-6) when factored
There are multiple ways to add three numbers together to get a sum of 17. One possible combination is 5 + 6 + 6, another is 9 + 4 + 4, and yet another is 7 + 5 + 5.
Prime numbers with hundreds of digits have been found, but there are still more to come that haven't been found yet. It's not possible to add up all the prime numbers, because nobody knows what they all are yet. Since there is no last prime number (this was proved 2000 years ago by Euclid), the sum of all prime numbers is infinite.
-10 and 4,
-155
ok, if you multiply ten by one you get ten. If you multiply ten by two you get twenty. If you multiply ten by three you get thirty. If you multiply ten by four you get forty. Sensing a trend here yet? All those things are multiples of ten. Basically, if a number ends in a zero, it's a multiple of ten.
841.2625
If multiplying 3 digit numbers with 2 digit numbers. For example; 345 x 92= First you will start with 2 by multiplying it by 5 then carry the 1 above the 4 then multiply the "2" with 4 then add the number on-top of the 4 which is 1 and it will give you 9. 4 x 2= 8+1=9. Then times the 2 by 3 which is 6. That is not your answer, yet. 690 plus the amount you get by multiplying 9 by every number, 5 then carry the number, 4 times 9, plus the number above it, then carry the 3 on top of the 3. Then add your total to 690 or what ever your equation is.
To factor quadratic trinomials, we find the two numbers which add to a certain number, and multiply to equal a certain number. Let me explain using the general form of a quadratic trinomial: ax2 + bx + c. If the quadratic trinomial is monic (coefficient on x2 is 1), then you simply find two numbers which add up to the coefficient of x (b) and multiply to give the constant (c). For example: The monic quadratic trinomial x2 - 5x + 6. Two numbers which add up to to give -5 and multiply to give 6 are -3 and -2. (-3 + -2 = -5; -3 x -2 = 6). Therefore the factors are (x - 3)(x-2). If the quadratic trinomial is non-monic (coefficient on x2 is greater than 1), then there's a slightly different method to go around solving them. I'll show this through the example: 2x2 + 5x - 3. We start off by changing the coefficient by multiplying it by the coefficient of x2 (in this case, 2). So the new coefficient will by -6. Then we split the equation into two factors (2x )(2x ) [They are blank because we don't know the numbers yet], and divide the factors by the coefficient of x2 (which is 2). So we have (2x )(2x ) divided by 2. Then we use the method of solving monic quadratics, and find two numbers which add to give +5, and multiply to give -6 (the new constant). In this case, the numbers are +6 and -1. (6 + -1 = 5; 6 x -1 = -6). So we put in our two numbers to get (2x + 6)(2x - 1) all over 2. Lastly, we make sure we factorise any of the factors [(2x + 6) can be factored as 2(x + 3)] to get 2(x+3)(2x-1) all over 2. And we just cancel out both twos on the numerator and denominator, and we are left with (x + 3)(2x - 1). One last example for non-monic quadratics: 4x2 + 7x - 2. First step: Multiply coefficient of x2 with constant to get new constant (4 x -2 = -8). Then we put the coefficient of x2 over the two factors we are yet to find. So we get (4x )(4x ) divided by 4. We then find the two numbers which add to give 7 and multiply to give -8, which are +8 and -1. We then have (4x + 8)(4x - 1) all over 4. Factorise whatever we can, to get 4(x+2)(4x-1) all over 4. Cancel out the 4s and we are left with (x + 2)(4x - 1).
Multiply the two numbers together as if there were no decimal places. But if there are any zeros at the end of the multiple don't get rid of them (yet). Count the number of digits after (to the right of) the decimal points in the two numbers. Add them together. That is the number of digits after the decimal that you want in the answer. So to calculate 1.25 * 3.4 125*34 = 4250 You have 2 digits after the decimal in 1.25 and 1 in 2.4 - a total of 3 So you need 3 digits after the decimal in the answer, which gives 4.250 You can THEN get rid of the trailing zero(s) and simplify to 4.25
Find out what two numbers add up to -8 yet when mutiplied they produce 12 and so: x squared-8x+12 = (x-2)(x-6) when factored
-0.5625
Any type of triangle will have angles that add up to 180o. yet two angles of an isosceles triangle are equal
There are multiple ways to add three numbers together to get a sum of 17. One possible combination is 5 + 6 + 6, another is 9 + 4 + 4, and yet another is 7 + 5 + 5.
Prime numbers with hundreds of digits have been found, but there are still more to come that haven't been found yet. It's not possible to add up all the prime numbers, because nobody knows what they all are yet. Since there is no last prime number (this was proved 2000 years ago by Euclid), the sum of all prime numbers is infinite.