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How do you multiply 3 digit numbers with 2 digit numbers?
If multiplying 3 digit numbers with 2 digit numbers. For example; 345 x 92= First you will start with 2 by multiplying it by 5 then carry the 1 above the 4 then multiply the "2" with 4 then add the number on-top of the 4 which is 1 and it will give you 9. 4 x 2= 8+1=9. Then times the 2 by 3 which is 6. That is not your answer, yet. 690 plus the amount you get by multiplying 9 by every number, 5 then carry the number, 4 times 9, plus the number above it, then carry the 3 on top of the 3. Then add your total to 690 or what ever your equation is.
How do you factor x squared minus 8x plus 12?
Find out what two numbers add up to -8 yet when mutiplied they produce 12 and so: x squared-8x+12 = (x-2)(x-6) when factored
How do you find where to place the decimal point after multiplying 2 decimals?
Multiply the two numbers together as if there were no decimal places. But if there are any zeros at the end of the multiple don't get rid of them (yet). Count the number of digits after (to the right of) the decimal points in the two numbers. Add them together. That is the number of digits after the decimal that you want in the answer. So to calculate 1.25 * 3.4 125*34 = 4250 You have 2 digits after the decimal in 1.25 and 1 in 2.4 - a total of 3 So you need 3 digits after the decimal in the answer, which gives 4.250 You can THEN get rid of the trailing zero(s) and simplify to 4.25
How many different ways can you add three numbers together to add up to 17?
There are multiple ways to add three numbers together to get a sum of 17. One possible combination is 5 + 6 + 6, another is 9 + 4 + 4, and yet another is 7 + 5 + 5.
Was the sum of all prime numbers?
Prime numbers with hundreds of digits have been found, but there are still more to come that haven't been found yet. It's not possible to add up all the prime numbers, because nobody knows what they all are yet. Since there is no last prime number (this was proved 2000 years ago by Euclid), the sum of all prime numbers is infinite.
