x^(2) - 8x + 12
Write down all the pairs of factors of '12'. They are ( 1,12) , ( 2, 6) , ( 3 ,4).
Select a pair that add to '8' . Viz, ( 2,6).
Set up brackets
( x 6)(x 2)
Which signs????
Since '12' is positive (+), then both the signs are the same.
Since '8' is negative(-), then both signs are negative.
Hence
( x - 6)(x - 2)
Fully factored . Done!!!!!!
It is x^2 -13x +12 = (x-1)(x-12) when factored
x2+2x-120 = (x+12)(x-10) when factored
133
Factor out a 22(X2 + X - 12)2(X - 3)(X + 4)===========
It is x^2 -x -12 is (x+3)(x-4) when factored
(x + 12)(x - 3)
(x - 5)(x + 12)
(6x - 1)(6x - 1)
It is x^2 -13x +12 = (x-1)(x-12) when factored
The expression x2 + 1x - 12 can be factored out as (x - 3)(x + 4)
x2+2x-120 = (x+12)(x-10) when factored
x2 + x - 12 = (x + 4) (x - 3)
(n - 4)(n - 12)
133
(x - 4)(x - 3)
(2x - 4)(2x + 3) The key is to look for all the factor pairs of 12.
Factor out a 22(X2 + X - 12)2(X - 3)(X + 4)===========