575 = 5 x 5 x 23. Consecutive factors therefore 23 & 25.
And in case that's 2, 3 and 5, try 30 and 60.
two numbers that have factors of 2, 5 and 7 are 70 and 140.
The prime numbers (factors) of 115 are: 5 and 23
1, 5, 23, 1151, 2, 5, 10, 23, 46, 115, 230
The factors of the set are 1,2,3,5. All three numbers are primes, so each has just two factors: itself and 1.2 = 1, 23 = 1, 35 = 1, 5
Factors refer to whole numbers, not decimals.
If that's 23 and 5, 115 and 230 If that's 2, 3 and 5, 30 and 60
The two numbers are 9 and 23. 23-9 = 14 23-(2*9) = 5
Since 115 ends in five, it will divide by '5'. Hence '5' is one of the factors. 5)115 = 23 Hence '23' is the other factor. Since '23' is a prime number, there are no other factors for 115 , but 5, and 23. except '1' & 115'.
The number 21 would be the answer. 19 and 23 only have two factors, 1 and themselves, as they are prime numbers. 25 only has 1, 25 and 5. 21 has 1, 21, 3 and 7 for 4 possible factors.
10, 20, and 30 all have factors of 2 and 5