34
391
8 and 5
8 and -5
The factor pairs of 40 are (40,1)(20,2)(10,4)(8,5) None of them total 3. If that was -40, you could use 8 and -5
The numbers are 25 and 15
If the product of the two numbers is the sum times 24, then the product of the two numbers is 2400. 40 times 60 is 2400, and 40 plus 60 is 100. The two numbers are 40 and 60.
391
37
1/x + 1/y = (y+x)/xy But y + x = sum = 150, and xy = product = 40 So sum of reciprocals = 150/40 = 3.75
9 and -40 9 + -40 = -31 9 x -40 = -360
23 and 32
8 and 5
8 and -5
20 and 20.
The two numbers that add to -6 and multiply to -40 are -10 and 4. This is because -10 + 4 = -6 and -10 * 4 = -40. This type of problem can be solved by setting up a system of equations where the sum of the numbers is -6 and the product of the numbers is -40, then solving for the two numbers.
The sum of two numbers between 20-40 is 58. The difference is 12
The factor pairs of 40 are (40,1)(20,2)(10,4)(8,5) None of them total 3. If that was -40, you could use 8 and -5