The probability is 8/36 = 4/9
The probability is 8/36 = 4/9
The probability is 8/36 = 4/9
The probability is 8/36 = 4/9
Assuming these are regular dice, the probability is 1.
two dice are thrown once. write all the possible outcomes. find the probability of getting: (i) a total of 12 (ii) a total of 3 (iii) a total of 8
The probability is 8/36 or 2/9
Probability that the sum is 6 = 5/36 Probability that the sum is 7 = 6/36
There is an approximately 8% chance of that, or 1 out of 12.
Assuming these are regular dice, the probability is 1.
two dice are thrown once. write all the possible outcomes. find the probability of getting: (i) a total of 12 (ii) a total of 3 (iii) a total of 8
The probability is 8/36 or 2/9
Two standard dice cannot have a sum greater than 12. The probability, then, of getting a sum greater than 15 is zero.
5/36 or 13.9%.
Probability that the sum is 6 = 5/36 Probability that the sum is 7 = 6/36
When rolling one die, the probability of getting a 4 is 1 in 6, or 0.1667. If two dice are rolled, you get two unrelated chances of rolling at least one 4, so the probability is 2 in 6, or 0.3333.
There is an approximately 8% chance of that, or 1 out of 12.
There are 36 permutations of two dice. Of these, 9 have a sum of 5 or 6, so the probability of rolling a sum of 5 or 6 on two dice is 9 in 36, or 1 in 9, or about 0.1111.
There are 36 possible outcomes. Of these the following 8 meet the requirements: (1,3), (2,2), (3,1), (1,5), (2,4), (3,3), (4,2) and (5,1). So the probability of 4 or 6 is 8/36 or 2/9
It is 15/36 = 5/12
5 out of 12