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Plot the given points on a suitable graph paper and construct 2 opposite equilateral triangles which will give a 3rd vertex of (2+square root of 3, 2-square root of 12) or a 3rd vertex of (2-square root of 3, 2+square root of 12) and each equal length of the triangle is 2 Times Square root of 5

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7y ago
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7y ago

The two possible locations are:[2 + sqrt(3), 2 - 2*sqrt(3)] and [2 - sqrt(3), 2 + 2*sqrt(3)].

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Q: Where is the 3rd vertex of an equilateral triangle when its other vertices are at 0 1 and 4 3 on the Cartesian plane?
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