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If all four prime numbers were odd then the sum would be an even number.
Therefore, one of the primes is 2.
The problem can now be simplified to which 3 prime numbers add up to 373.
There are many solutions which can be easily determined with the aid of a list of the prime numbers up to 373. For example :-
353+ 17 + 3 : 353 + 13 + 7
349 + 19 + 5 : 349 + 17 + 7 : 349 + 13 + 11
347 + 23 + 3 : 347 + 19 + 7 : 347 + 13 + 13.
The distinct prime factors of 550 are 2, 5 and 11. They add up to 18.
If the numbers are prime numbers, the prime factor of each number is the number itself. If the numbers are not prime numbers, the prime factors of each number are each of the prime numbers by which the number in question can be divided without a remainder.
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All composite numbers can be expressed as unique products of prime numbers. This is accomplished by dividing the original number and its factors by prime numbers until all the factors are prime. A factor tree can help you visualize this.Example: 210210 Divide by two.105,2 Divide by three.35,3,2 Divide by five.7,5,3,2 Stop. All the factors are prime.2 x 3 x 5 x 7 = 210That's the prime factorization of 210.
The prime factors of a number by multiplying each other. You can also use exponents. a prime factorization is when you divide a number and see what all of the prime (odd) numbers make up that number. EX. 9 / \ 3 3 then you would circle the 3's because they are prime.