22
11
Let the smaller number be ( x ). Then the larger number can be expressed as ( 3x + 2 ). According to the problem, their sum is ( x + (3x + 2) = 22 ). Simplifying, we get ( 4x + 2 = 22 ), so ( 4x = 20 ) and ( x = 5 ). Thus, the smaller number is 5, and the larger number is ( 3(5) + 2 = 17 ). The two numbers are 5 and 17.
17-5=12 !
5*5*17 = 425
The smaller integer is 17.
It is the smaller divided by the bigger. For 5 and 17, the 5 is 5/17 of the 17.
They are 5 and 6 because 5+(2*6) = 17
11
If two fractions have the same [positive] denominator, then the smaller numerator implies the smaller fraction. Furthermore, the ratio of the numerators is the ratio of the fractions. So, for example, if you have 3/17 and 5/17 then, since 3 < 5, it follows that 3/17 < 5/17 and the two fractions are in the ratio 3:5. That is, the first fraction is 3/5 of the second. All of the above remains true if you replace 17 by any other positive number (including an irrational number).
.16 is smaller than .5
No. 4 is smaller than 17 so it cannot be divisible by 17.
85 (=17*5). The middle term is 5. There are 8 terms bigger than 5 and 8 smaller. The term smaller than 5 and next to it is 5 - r The term bigger than 5 and next to it is 5 + r So these two average 5. Similarly, the next pair outwards average 5; and so on. So the sum of the progression is equivalent to the sum of 8 pairs of numbers whose average is 5 and the middle term which is 5 ie 17 lots of 5.
If 5 and 92 are both factors, 5 is the smaller one.
12
17/10 = 1.7
17-5=12 !
5*5*17 = 425