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85 (=17*5).

The middle term is 5. There are 8 terms bigger than 5 and 8 smaller.

The term smaller than 5 and next to it is 5 - r

The term bigger than 5 and next to it is 5 + r

So these two average 5.

Similarly, the next pair outwards average 5; and so on.

So the sum of the progression is equivalent to the sum of 8 pairs of numbers whose average is 5 and the middle term which is 5 ie 17 lots of 5.

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Q: Find the sum of an arithmetic progression of seventeen terms whose middle term is 5?
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