None of them.
None of them.
None of them.
None of them.
None of them.
The question does not contain an equation nor an inequality. There cannot, therefore be any ordered pairs which can satisfy an expression.
13
(1, 0.2), (2, 0.1)
To find the ordered pairs in any equation, just plug in any number for x and solve for y. If your equation is meant to be y=1+5x, then if x=0 then y=1+5*0, y=1 so the first ordered pair would be (0,1) If your equation is meant to be y=(1/5)x, then if x=0 then y=(1/5)*0, y=0, so the first ordered pair would be (0,0)
There are infinitely many ordered pairs that satisfy this equation. Supply any value for x, then solve for y to get the other part of the pair.
The question does not contain an equation nor an inequality. There cannot, therefore be any ordered pairs which can satisfy an expression.
There are infinitely many ordered pairs tat are solutions. They are all points on the line represented by 5x-6y = 13
13
7
None. There is no equation or inequality in the question - only an expression. An expression cannot have a solution.
(1, 0.2), (2, 0.1)
To find the ordered pairs in any equation, just plug in any number for x and solve for y. If your equation is meant to be y=1+5x, then if x=0 then y=1+5*0, y=1 so the first ordered pair would be (0,1) If your equation is meant to be y=(1/5)x, then if x=0 then y=(1/5)*0, y=0, so the first ordered pair would be (0,0)
how many solutions does the equation have? 4x+1=5+2(2-4) a. one solution b. infinite solutions c. no solution
There are infinitely many ordered pairs that satisfy this equation. Supply any value for x, then solve for y to get the other part of the pair.
If you mean: 2x+y = -6 and 5x-3 = 7 then the solutions are x = -1 and y = -4
The solutions to the quadratic equation are: x = -1 and x = 6
If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7