No, and I can prove it: -- The product of two rational numbers is always a rational number. -- If the two numbers happen to be the same number, then it's the square root of their product. -- Remember ... the product of two rational numbers is always a rational number. -- So the square of a rational number is always a rational number. -- So the square root of an irrational number can't be a rational number (because its square would be rational etc.).
No.
No. Lots of square roots are not rational. Only the square roots of perfect square numbers are rational. So for example, the square root of 2 is not rational and the square root of 4 is rational.
Some square roots are rational but the majority are not.
Every integer is a rational number, and some integers are perfect squares. These are the only rational numbers to have an integral square root.
They are NOT rational numbers, so the question is misguided.
Yes, for example, square root of 2 x square root of 2 = 2.* * * * *No, the product of two rational numbers must always be rational.No.Proof :If you take rational number a/b and multiply by rational c/d you get ac/bd.Since ac and bd are each integral, the product is rational.
The square root of 2 times the square root of 2 is rational.
Yes. The square root of 81 is 9 - a natural number and all natural numbers are rational numbers.
No. The square roots of 2, 3 and 5, for a start, are not rational.
Because numbers such as pi, e and the square root of 2 are not rational.
Rational numbers whose square roots are whole numbers are themselves whole numbers. They are called square numbers, e.g. 1, 4, 9, 16, 25 and so on.