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Eula O'Hara

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3y ago
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11y ago

There are several ways.

Select any vertex and draw all the diagonals from that vertex. This divides the n-gon into (n-2) triangles.

You can show that the sum of the interior angles of the n-gon is the sum of the interior angles of these triangles.

Each triangle = 180 deg so (n-2) triangles = (n - 2)*180 degrees = 180n - 360 deg.

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Q: Why is it possible to fnd the sum of the angle measures of a n gon using the formula 180n-360?
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