Because impulse is the integral of the force over the time during which it was applied. Graphically, this is the area under the curve of force against time.
Force is rate of change of momentum. Even if you hit a brick wall you impart momentum to some of the atoms in it. The area under a graph of force against time is mathematically speaking the integral of the force with respect to time, as stated above. So it is the integral of the rate of change of momentum. But the integral of a rate of change of anything, is simply the total change. In this case, the total change of momentum. For a large force applied for a very small time, that is called (defined to be) an impulse, and it results in a change of momentum. Strictly it doesn't have to be a small time for this to be true, but impulses are generally imagined as being short time events.
Yes, it is possible for the impulse of force to be zero even if the force is not zero. This can happen if the force is applied for such a short period of time that the area under the force-time graph, which represents impulse, is zero.
The momentum-time graph is the integral of the force-time graph. that is, it is the area under the curve of the f-t graph.The momentum-time graph is the integral of the force-time graph. that is, it is the area under the curve of the f-t graph.The momentum-time graph is the integral of the force-time graph. that is, it is the area under the curve of the f-t graph.The momentum-time graph is the integral of the force-time graph. that is, it is the area under the curve of the f-t graph.
Yes, a position-time graph can be created from a velocity-time graph by integrating the velocity values over time. By finding the area under the velocity-time curve, you can determine how the position of an object changes over time.
distance
The area under a v/t graph is how far you've gone. Choose a point on the time axis, read off the speed and find the area underneath. If its a straight line graph, all you have to do is find the area of the triangle. This area is the distance travelled in this particular time. Repeat for several more points on the time axis. Plot distance against time.
It is not, if it is a graph of force against acceleration.
To determine the impulse from a force-time graph, you can find the area under the curve of the graph. Impulse is equal to the change in momentum, which is calculated by multiplying the force applied by the time over which it is applied. The area under the force-time graph represents the impulse exerted on an object.
A Force-time graph shows the variation of force with respect to time. More usefully the area under such a graph gives the quantity Ft or impulse, which is equal to the change in momentum of an object. Ft = Mv-Mu
To obtain the take-off impulse from a force vs. time graph, calculate the area under the curve of the graph. The impulse is represented by this area, which quantifies the total momentum change imparted to the object. If the graph has both positive and negative values, ensure to account for the direction of the forces when calculating the area. This can be done using geometric shapes or integration, depending on the complexity of the graph.
Yes, it is possible for the impulse of force to be zero even if the force is not zero. This can happen if the force is applied for such a short period of time that the area under the force-time graph, which represents impulse, is zero.
The area under a force-displacement graph represents the work done on an object. Work is defined as the force applied to an object multiplied by the distance the force is applied over.
The momentum-time graph is the integral of the force-time graph. that is, it is the area under the curve of the f-t graph.The momentum-time graph is the integral of the force-time graph. that is, it is the area under the curve of the f-t graph.The momentum-time graph is the integral of the force-time graph. that is, it is the area under the curve of the f-t graph.The momentum-time graph is the integral of the force-time graph. that is, it is the area under the curve of the f-t graph.
The area under a force-distance graph represents the work done. It is equal to the force applied multiplied by the distance moved in the same direction as the force.
no, work done is the area under a force-distance graph
The area under a displacement over force graph represents work done. It indicates the amount of energy transferred when a force acts over a particular displacement.
The area under a graph of force against distance (or extension, if it's a spring) represents the work done by that force. Since it sounds like you're talking about a spring, you should know that the area would represent the work done to stretch the spring that distance, and also represents the amount of elastic potential energy contained by the spring.
It is the force constant of the material in N/m. So you can substitute it into the equation F=kx (F=force, k=force constant or gradient in N/m, x = extension) You would expect the extension to be on the y-axis normally since it is the measured value. However since you want to use the graph to calculate certain values it is on the x-axis (you can also find the work done by the force by finding the area under the graph) Also it allows you to divide the y-axis values by the cross-sectional area and x-axis values by original length to get a stress vs strain graph where you can use the gradient to find the Young modulus of the material.