That's because lines, or curves, can have different slopes.
No, a positive slope is not always steeper than a negative slope. The steepness of a slope is determined by its absolute value, regardless of its sign. For example, a slope of +3 is steeper than a slope of -2, but a slope of +1 is less steep than a slope of -5. Thus, it depends on the specific values of the slopes being compared.
Perpendicular lines have slopes whose product is -1. As this is always true, if we think of .33 as about 1/3, then the perpendicular line would have a slope of -1/(1/3) which is -3.
The slope was always there
For any two perpendicular lines (save a vertical and a horizontal one), the product of their slopes is always -1. For two perpendicular lines with one having a slope of -2, the other will have a slope equal to -1 divided by -2, which equals 1/2.
The product of the slopes of two perpendicular lines is always -1. If one line has a slope of ( m_1 ) and the other has a slope of ( m_2 ), the relationship can be expressed as ( m_1 \cdot m_2 = -1 ). This means that if you know the slope of one line, you can find the slope of the perpendicular line by taking the negative reciprocal of that slope.
No.
The slope is always positive A negative slope will always pass through quadrant II and IV
No, a positive slope is not always steeper than a negative slope. The steepness of a slope is determined by its absolute value, regardless of its sign. For example, a slope of +3 is steeper than a slope of -2, but a slope of +1 is less steep than a slope of -5. Thus, it depends on the specific values of the slopes being compared.
Perpendicular lines have slopes whose product is -1. As this is always true, if we think of .33 as about 1/3, then the perpendicular line would have a slope of -1/(1/3) which is -3.
The slope was always there
Horizontal lines always have a slope of 0.
The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.The slope of the perpendicular is the negative reciprocal of the slope of a line. In this case, - (1 / -1) = 1.
A perpendicular lines slope is always the negative or opposite reciprocal of a lines slope. Therefore, if your slope is -13/1 then the perpendicularity of the other line is 1/13. The 13 would change positive there fore its its already a negative number then change it posiive.
The slope of line AB will be 1/2. Two parallel lines will always have the same slope, so if you know the slope of one line that is parallel to another, you know the other line's slope.
For any two perpendicular lines (save a vertical and a horizontal one), the product of their slopes is always -1. For two perpendicular lines with one having a slope of -2, the other will have a slope equal to -1 divided by -2, which equals 1/2.
The product of the slopes of two perpendicular lines is always -1. If one line has a slope of ( m_1 ) and the other has a slope of ( m_2 ), the relationship can be expressed as ( m_1 \cdot m_2 = -1 ). This means that if you know the slope of one line, you can find the slope of the perpendicular line by taking the negative reciprocal of that slope.
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