Write a program to find the largest of three numbers?

Answer 1

This is best done with an array; that way, you can easily extend to more than three numbers. In Java, it would be something like this:

int myNumbers[] = {1, 5, 3};

int max = myNumbers[1];

for (int i = 1; i < myNumbers.length(); i++)
if (myNumbers[i] > max) max = myNumbers[i];

This is best done with an array; that way, you can easily extend to more than three numbers. In Java, it would be something like this:

int myNumbers[] = {1, 5, 3};

int max = myNumbers[1];

for (int i = 1; i < myNumbers.length(); i++)
if (myNumbers[i] > max) max = myNumbers[i];

This is best done with an array; that way, you can easily extend to more than three numbers. In Java, it would be something like this:

int myNumbers[] = {1, 5, 3};

int max = myNumbers[1];

for (int i = 1; i < myNumbers.length(); i++)
if (myNumbers[i] > max) max = myNumbers[i];

This is best done with an array; that way, you can easily extend to more than three numbers. In Java, it would be something like this:

int myNumbers[] = {1, 5, 3};

int max = myNumbers[1];

for (int i = 1; i < myNumbers.length(); i++)
if (myNumbers[i] > max) max = myNumbers[i];

Answer 2

This is best done with an array; that way, you can easily extend to more than three numbers. In Java, it would be something like this:

int myNumbers[] = {1, 5, 3};

int max = myNumbers[1];

for (int i = 1; i < myNumbers.length(); i++)
if (myNumbers[i] > max) max = myNumbers[i];