If X - 8 = -1 then X = -1 +8 Therefore X = 7
(x+8)(x-1)=0 x+8=0 x=-8 x-1=0 x=1 Therefore, the zeroes are -8 and 1.
(-1) x 8 = -8 (-2) x 4 = -8 (-4) x 2 = -8 (-8) x 1 = -8 (-16) x 0.5 = -8 (-24) x 1/3 = -8 (-32) x 0.25 = -8 (-64) x 0.125 = -8 . . etc.
7x/4 = 1/8 (7x/4) x (8) = (1/8) x (8) 14x = 1 x = 1/14
Equation 1: y = 8/x => xy = 8 Equation 2: y = 7+x Substitute Equation 2 into Equation 1: x(7+x) = 8 x2+7x-8 = 0 => (x-1)(x+8) = 0 x = 1 or x = -8 Substitute these values into Equation 2: When x = 1, y = 8 When x = -8, y = -1 The coordinates are (-8,-1) and (1,8)
x/8 - 1 = 0 (8)(x/8)- (8)(1) = (8)(0) x - 8 = 0 x - 8 + 8 = 0 + 8 x = 8
Such that 83 = 8 x 8 x 8 = 512, 8-3 = 1/8 x 1/8 x 1/8 = 1/512
8 x 8 = (8 x 1) x (8 x 1)
1/8 of 8 = 1 because................ of = x (multiplication) and....................... 1/8 x 8 = 1/8 x 8/1 = 1 numerator (1) x numerator (8) = 8 so............. 8 is the numerator denominator (8) x denominator (1) = 8 so.............. 8 is the denominator also and........... 8/8 = 1 so................. 1/8 of 8 is 1
If X - 8 = -1 then X = -1 +8 Therefore X = 7
(x+8)(x-1)=0 x+8=0 x=-8 x-1=0 x=1 Therefore, the zeroes are -8 and 1.
1, 2, 4, 8: 1 x 8, 2 x 4, 4 x 2, 8 x 1
(-1) x 8 = -8 (-2) x 4 = -8 (-4) x 2 = -8 (-8) x 1 = -8 (-16) x 0.5 = -8 (-24) x 1/3 = -8 (-32) x 0.25 = -8 (-64) x 0.125 = -8 . . etc.
7x/4 = 1/8 (7x/4) x (8) = (1/8) x (8) 14x = 1 x = 1/14
There are 8 ones in 8 (1 x 8 = 8). There are also 8 eighths in 1 (8 x 1/8 = 1).
If 3x + 5x = -8, what is x + 1? 3x + 5x = -8 8x = -8 x = -1 x + 1 = -1 + 1 = 0
Equation 1: y = 8/x => xy = 8 Equation 2: y = 7+x Substitute Equation 2 into Equation 1: x(7+x) = 8 x2+7x-8 = 0 => (x-1)(x+8) = 0 x = 1 or x = -8 Substitute these values into Equation 2: When x = 1, y = 8 When x = -8, y = -1 The coordinates are (-8,-1) and (1,8)