If [ y = x + 2 ], then x is not -1 when y = 5.If [ y = x + 2 ],then when x = -1, y = 1,and when y = 5, x = 3.
In the equations Y=X-1 and Y=-X+1, the solution is (1,0)
solution: y = 0 x = -1
If x = sin θ and y = cos θ then: sin² θ + cos² θ = 1 → x² + y² = 1 → x² = 1 - y²
The solution is: x = 1 and y = -1
xy = x ÷x y = 1
When x = 1 then y = 4
x equals -12 and y equals 1/4 of -12, so y = -3.
If: x = -5 Then: y = (3*-5)-1 = -16
If y(x) = 1/3x, y(-18) = 1/[3(-18)] = -1/54.
Y is undefined because the line x=1 never crosses the y axis.
1