r = 5z 15z = 3y (divide by 3 to both sides) 5z = y r = y
Closure: If x and y are any two elements of Rthen x*y is an element of R.Associativity: For and x, y and z in R, x*(y*z) = (x*y)*z and so, without ambiguity, this may be written as x*y*z.Identity element: There exists an element 1, in R, such that for every element x in R, 1*x = x*1 = x.Inverse element: For every x in R, there exists an element y in R such that x*y = y*x = 1. y is called the inverse of x and is denoted by x^-1.The above 4 properties determine a group.
There is no such number. For suppose x was a number such that it keft the same remainder r, when divided by 99 and 204. Then x = 99a + r and x = 204b +r for some integers a and b. Consider y = x + 99*204 then y > x Now y = (99a + r) + 99*204 = 99*(a+204) + r so y leaves a remainder of r when divided by 99. Also y = (204b + r) + 99*204 = 204*(b+99) + r so y leaves a remainder of r when divided by 204. This contradicts the proposition that x is the maximum such number.
A circle centre (0, 0) and radius r has equation x² + y² = r² The circle x² + y² = 36 has: r² = 36 → radius = 6
(x,y) -> (x-3, y+4)
u r a g*y noob wikiansewers is sh*t
of course rockets r in Halo 3! y wodnt they be???!!! GO PLASMA PISTOL NOOBS
thank you noob
Noob i r not gun tell
you r a noob is it any of your bussiness?
It is y. Every third letter is r, immediately followed by y, and since 117 is divisible by 3, it is r. Therefore, 118 is y.
noob how r we supose to kno
It means "you are a newbie" - if you break it down- u r a noob
Known Ratio gives: X/Y = R Known Area gives: X*Y = A R and A are known. Two equations. Two unknowns. X = R*Y R*Y*Y = A Y^2 = A/R Y = SQRT(A/R) X = R*SQRT(A/R)
a noob means no exprience
r=y
if: r = 5z 15z = 3y then: z = y/5 r = 5(y/5) r = y