Your question is ambiguous.
Possible answers are:
1. 333 (333 in base 5 = 333 in base 5). You must properly specify an alternate base if you want a conversion between 2 different bases.
2. 2313 (converted 333 base 10 to base 5)
3. 93 (converted 333 base 5 to base 10)
Method:
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If you want to know 333 base 10 value in a base 5 system, then your answer is: 2313.
Base 10 to Base 5 Conversion Method:
333 / 5 = 66.6 .6*5 = 3
66 / 5 = 13.2 .2*5 = 1
13 / 5 = 2.6 .6*5 = 3
2 / 5 = .4 .4*5 = 2
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If you want to know 333 base 5 value in a base 10 system, then your answer is: 93.
Base 5 to Base 10 Conversion Method:
5^2=25 * 3 = 75
5^1= 5 * 3 = 15
5^0=1 * 3 = 3
75 + 15 + 3 = 93
The absolute value of any number is the same number as a positive value. Therefore the absolute value of -333 is +333, or just plain 333.
Coefficient -5. Base: x. exponent: 3. Value: depends on the value of x. or Base: (-5)1/3x, exponent: 3
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The value of (\log 5) depends on the base of the logarithm. If it is the common logarithm (base 10), (\log_{10} 5 \approx 0.699). If it is the natural logarithm (base (e)), (\ln 5 \approx 1.609). For base 5, (\log_5 5 = 1).
1000.
The base can have any positive value.
The base of log, if unspecified, is taken to be 10 so you would be finding the value of the logarithm of 5 to the base 10.This is the value x, such that 10^x = 5.
333
The Kb value for the conjugate base CN- (cyanide ion) is 2.5 x 10^-5.
The greatest value a digit can have in base for is 3. Thus the largest three-digit number in base for would be 333. In base 10, this number is 3x16 + 3x4 + 3 = 63 Therefore 63 is the largest digit that would be three digits in base 4.
66.6
This question is ambiguous, because an alternate base must be specified if you want a conversion between two different bases. However, assuming that 93 is in the common modern decimal base, 93 = (3 X 52) + (3 X 5) + (3 X 1), so the decimal number 93 would be written as 333 in base 5.