Slightly over 50 grams; the half-life of Pu-239 is around 24110 years, so in 24000 years a little less than half will have decayed to U-235.
24,000 days = 65.71 years.
10 grams... If the half-life is 100 years, that means after 100 years, half the original mass remains. After another 100 years, the mass is halved again. 40/2=20... 20/2=10.
That depends what assumptions you make about what the 5 grams of matter is made of.
I will try to make the answer simple for you. Half life is 1600 years. So After 1600 years you have half the mass left. That is 10 grams. After another 1600 years, you will be left with half the mass of 10 grams. That is five grams. So after total 3200 years you will be left with 5 grams of mass of the Ra-226 left with.
100 grams
24000 a month
0,5 grams
It depends on the substance and its rate of decay. The amount remaining can be calculated using the substance's half-life and the initial amount present.
100 grams
If the substance has a half-life of 10 years, there would be 10 half-lives in a 100-year span. Each half-life reduces the amount by half, so after 100 years, 1/2^10 = 1/1024 grams of the sample would remain.
Assuming interest compounded annually, at the end of 29 years there will be only 270 in the account so it will not be possible to take 24000 in the 29th year.
After 28 years, half of the 2.5 grams (1.25 grams) would remain. After another 28 years (56 years total), only 0.625 grams would remain, and so on. The amount of the radioactive element left can be calculated using the formula: remaining amount = initial amount * (1/2)^(years/half-life), where the initial amount is 2.5 grams and the years is the given time.