Without information about the bias, there can be no possible answer. You cannot even say that the probability of 4 is not 0.25 since suppose the spinner has the following probabilities:
Pr(1) = 0.1 Pr(2) = 0.4 Pr(3) = 0.25 Pr(4) = 0.25
is clearly biased - in favour of 2, but the probability of 4 is not affected by the bias.
ok I'm sure not many people will be asking this but a biased spinner is basically a spinner that is unfair or not accurate
If the coin is not biased, the answer is 0.375
I am assuming that this die is fair die and the coin is not biased. The probability of getting a number less than 3 is the probability of rolling a 1 or a 2 i.e. 1/6 + 1/6 = 2/6 which simplifies to 1/3. The probability of getting a head when you flip a fair coin is 1/2. Both are independent events, so the probability of getting a number less than 3 and getting a head is 1/3 x 1/2 = 1/6. One can get the same answer from a sample space diagram
Multiply the probability by the number of times the experiment was carried out. 0.6x10=6
the probability would be 50 to 50 chancesThere's generally a 50% chance it will come up tails, but some coins have heavier designs on one side, so these may be more biased to a head or a tail over the term.If it is a fair coin, then 0.5
Probability of getting a head or tail is not equal
ok I'm sure not many people will be asking this but a biased spinner is basically a spinner that is unfair or not accurate
The probability of heads is 0.6 and that of tails is 0.4. Since the probabilities are not 0.5, it is a biased coin. That is the answer!
0.63 = 0.216
If the coin is not biased, the answer is 0.375
I'm guessing this is a probability question. A die (or coin, or spinner, or roulette wheel, or other method of choosing something randomly) is fair if each possibility (1,2,3,4,5,6) has an equal chance of coming up. Anything that isn't fair is biased. For example a die that has been weighted to make 6s come up is biased.
Assuming that each sector is coloured differently and exactly on of them is red, then the probability that the last spin of 6 lands on red is 1/3. Each spin is independent of the previous spin - the spinner has no knowledge to affect its outcome. The gambler's fallacy is that an inanimate object has some "memory" that after a long run of not showing a result it will show that result, or after a long run of showing a result it will not show that result, on the next turn. In fact, in the second case, if the probability is so low that a long run of an event is not very likely (eg tossing a coin 11 times and every toss is a head), then it is likely that the object is actually biased and is more likely than normal probability would suggest to favour repeating the result (as 11 heads in a row is unlikely (but not impossible), it is likely that the coin, or how it is tossed, is biased and so the chance of another 12th head is going to be (much) greater than the normal probability of 1/2).
Probability = number_of_ways_of_success / total_number_if_outcomes As a cube has 6 faces and you have only specified that it has five numbers (1-5), one of those numbers must be repeated, thus the probability of rolling a 5 depends upon whether there is one or two sides bearing a 5: If there is only 1 side bearing a 5, then it is 1/6 If there are 2 sides bearing a 5, then it is 2/6 = 1/3 If you meant a five sided solid, then there is no such regular solid and some face(s) would be biased to appear and it would depend upon which face has the 5. However, an icosahedron has 20 faces and the numbers 1-5 could be repeated 4 times each, meaning that the probability of rolling a 5 would be 4/20 = 1/5. If you had a regular pentagonal spinner, with each digit corresponding to an edge, then the probability of spinning a 5 would be 1/5. If you mean a standard die: a cube with six sides numbers 1-6 (and the 1-5 was a typographical error), then the probability is 1/6.
I am assuming that this die is fair die and the coin is not biased. The probability of getting a number less than 3 is the probability of rolling a 1 or a 2 i.e. 1/6 + 1/6 = 2/6 which simplifies to 1/3. The probability of getting a head when you flip a fair coin is 1/2. Both are independent events, so the probability of getting a number less than 3 and getting a head is 1/3 x 1/2 = 1/6. One can get the same answer from a sample space diagram
If it lands on a six 140 times then the estimated probability of a six is 140/400 = 0.35
Assuming the sides are labelled one to twenty and that all sides are the same shsp and size and that the dice in not biased in any way, then there will be a 50% chance of getting an odd number.
An unbiased die is a fair six-sided cube, where each face has an equal probability of landing face up when rolled. This means that each of the six numbers (1 through 6) has a 1/6 chance of being the outcome. In contrast, a biased die would favor certain numbers, leading to unequal probabilities. Unbiased dice are commonly used in games and probability experiments to ensure fairness.