P(A) chance of being a bolt = 50/200=1/4
P(B) i.e chance of a rusted item ( i.e bolt or nuts) =100/200=1/2
P(AB) = P ( OF BEING RUSTED AND BOLT)= 25/200= 1/8
P(A or B) = the probability that it is rusted or a bolt. = P(A) + P(B) -P(AB)=0.25+0.5-0.125=0.625
51/200
"Playing cards" are chosen at random.
The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.
3/4
Probability that a girl is chosen = 23/45 = .511 So, the probability that a boy is chosen = 1 - .511 = .489
What the answer
"Playing cards" are chosen at random.
The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.The probability of a single point being chosen is 0.
3/4
Probability that a girl is chosen = 23/45 = .511 So, the probability that a boy is chosen = 1 - .511 = .489
Q. A letter is chosen at random from the word STATistician.What is the probability that it is a vowel?What is the probability that it is T.
What the answer
For a single random choice from a standard deck, the probability is 1/13.For a single random choice from a standard deck, the probability is 1/13.For a single random choice from a standard deck, the probability is 1/13.For a single random choice from a standard deck, the probability is 1/13.
The probability that the birthdays of five persons chosen at random will fall in twelve different calender months is zero. You would need at least twelve persons to have a non zero probability.
1/6 if the letter is chosen at random.
The probability of a woman being chosen in this situation is 7/11.
49/9000
4 because in word perseverance we have 4 letters E