Probability = (number of successful outcomes) / (number of possible outcomes)
Possible outcomes: 6
Successful outcomes: 1
Probability = 1/6 = 16 and 2/3 percent.
When rolling one die, the probability of getting a 4 is 1 in 6, or 0.1667. If two dice are rolled, you get two unrelated chances of rolling at least one 4, so the probability is 2 in 6, or 0.3333.
1
5 to 1
The probability is 1/6.
To find the probability that an event will not occur, you work out the probability that it will occur, and then take this number away from 1. For example, the probability of not rolling two 6s in a row can be worked out the following way:The probability of rolling two 6s in a row is 1/6 x 1/6 = 1/36Thus the probability of not rolling two 6s in a row is 1 - 1/36=35/36.
When rolling one die, the probability of getting a 4 is 1 in 6, or 0.1667. If two dice are rolled, you get two unrelated chances of rolling at least one 4, so the probability is 2 in 6, or 0.3333.
To find the experimental probability of rolling a 6, you first need to determine the number of times a 6 was rolled during the experiment. Then, divide that number by the total number of rolls recorded in the table. The resulting fraction represents the experimental probability of rolling a 6. For example, if a 6 was rolled 5 times out of 30 total rolls, the experimental probability would be 5/30, which simplifies to 1/6.
1
The probability of rolling a 3 on a six-sided die in a single roll is 1/6. When rolling the die three times, the probability of getting at least one 3 can be calculated using the complement: first, find the probability of not rolling a 3 in three rolls, which is (5/6)³. Subtract this value from 1 to find the probability of rolling at least one 3 in three attempts.
Assuming that the random variable is the sum of the two numbers rolled, the answer is 3/36 or 1/12.
the probability is 1 out of 6
If it is a fair die that is rolled once, then the probability is 2/3.
The probability of rolling a 7 with 2 dice is 6/36; probability of rolling an 11 is 2/36. Add the two together to find probability of rolling a 7 or 11 which is 8/36 or 2/9.
5 to 1
There are 36 permutations of two dice. Of these, 9 have a sum of 5 or 6, so the probability of rolling a sum of 5 or 6 on two dice is 9 in 36, or 1 in 9, or about 0.1111.
To find the probability of rolling an even number on the first roll and a 1 on the second roll with a single die, we first note that the even numbers on a die are 2, 4, and 6. Thus, the probability of rolling an even number on the first roll is 3 out of 6, or 1/2. The probability of rolling a 1 on the second roll is 1 out of 6. Therefore, the combined probability is (1/2) * (1/6) = 1/12.
When rolling a pair of dice there are 6∙6 = 36 possible outcomes. The outcomes that give a sum of 5 are 4, [(1,4), (2,3), (3,2), (4,1)]. So the probability of not rolling a sum of 5 is: P(NOT 5) = 1 - P(5) = 1 - 4/36 = 32/36 = 8/9 = 0.8888... ≈ 88.9%