When rolling one die, the probability of getting a 4 is 1 in 6, or 0.1667. If two dice are rolled, you get two unrelated chances of rolling at least one 4, so the probability is 2 in 6, or 0.3333.
1
5 to 1
The probability is 1/6.
To find the probability that an event will not occur, you work out the probability that it will occur, and then take this number away from 1. For example, the probability of not rolling two 6s in a row can be worked out the following way:The probability of rolling two 6s in a row is 1/6 x 1/6 = 1/36Thus the probability of not rolling two 6s in a row is 1 - 1/36=35/36.
When rolling one die, the probability of getting a 4 is 1 in 6, or 0.1667. If two dice are rolled, you get two unrelated chances of rolling at least one 4, so the probability is 2 in 6, or 0.3333.
1
Assuming that the random variable is the sum of the two numbers rolled, the answer is 3/36 or 1/12.
the probability is 1 out of 6
If it is a fair die that is rolled once, then the probability is 2/3.
The probability of rolling a 7 with 2 dice is 6/36; probability of rolling an 11 is 2/36. Add the two together to find probability of rolling a 7 or 11 which is 8/36 or 2/9.
5 to 1
There are 36 permutations of two dice. Of these, 9 have a sum of 5 or 6, so the probability of rolling a sum of 5 or 6 on two dice is 9 in 36, or 1 in 9, or about 0.1111.
When rolling a pair of dice there are 6∙6 = 36 possible outcomes. The outcomes that give a sum of 5 are 4, [(1,4), (2,3), (3,2), (4,1)]. So the probability of not rolling a sum of 5 is: P(NOT 5) = 1 - P(5) = 1 - 4/36 = 32/36 = 8/9 = 0.8888... ≈ 88.9%
The probability of rolling an even die and then an odd die is (3 in 6) times (3 in 6), which is the same as (1 in 2) times (1 in 2), which is the same as 0.5 time 0.5, which is 0.25.
The probability is 1/6.
The probability is 35/36.