Three results are desirable and there are nine possible ones. That gives 3/9, aka 1/3, aka 33%
A spinner has the numbers 1 thru 9. What is the probability of P(less than 6)? Write the answer as a decimal.
The answer is 50%.
1/6
Probability questions are not all the same so there is not a single kind of answer: it depends on the nature of the question!
This is a probability question. Probabilities are calculated with this simple equation: Chances of Success / [Chances of Success + Chances of Failure (or Total Chances)] If I flip a coin, there is one chance that it will land on heads and one chance it will land on tails. If success = landing on heads, then: Chances of Success = 1 Chances of Failure = 1 Total Chances = 2 Thus the probability that a coin will land on heads on one flip is 1/2 = .5 = 50 percent. (Note that probability can never be higher than 100 percent. If you get greater than 100 you did the problem incorrectly) Your question is unclear whether you mean the probability that a coin will land on head on any of 8 flips or all of 8 flips. To calculate either you could write out all the possible outcomes of the flips (for example: heads-heads-tails-tails-heads-tails-heads-heads) but that would take forvever. Luckily, because the outcome of one coin flip does not affect the next flip you can calculate the total probability my multiplying the probabilities of each individual outcome. For example: Probability That All 8 Flips Are Heads = Prob. Flip 1 is Heads * Prob. Flip 2 is Heads * Prob. Flip 3 is Heads...and so on Since we know that the probability of getting heads on any one flips is .5: Probability That All 8 Flips Are Heads = .5 * .5 * .5 * .5 * .5 * .5 * .5 * .5 (or .58) Probability That All 8 Flips Are Heads = .00391 or .391 percent. The probability that you will flip a heads on any of flips is similar, but instead of thinking about what is the possiblity of success, it is easier to approach it in another way. The is only one case where you will not a heads on any coin toss. That is if every outcome was tails. The probability of that occurring is the same as the probability of getting a heads on every toss because the probability of getting a heads or tails on any one toss is 50 percent. (If this does not make sense redo the problem above with tails instead of heads and see if your answer changes.) However this is the probability of FAILURE not success. This is where another probability formula comes into play: Probability of Success + Probability of Failure = 1 We know the probability of failure in this case is .00391 so: Probability of Success + .00391 = 1 Probability of Success = .9961 or 99.61 percent. Therefore, the probability of flipping a heads at least once during 8 coin flips is 99.61 percent. The probability of flipping a heads every time during 8 coin flips is .391 percent.
Three results are desirable and there are nine possible ones. That gives 3/9, aka 1/3, aka 33%
A spinner has the numbers 1 thru 9. What is the probability of P(less than 6)? Write the answer as a decimal.
P(1 or 6)
21 is a number. You cannot write that as a probability since it is not an event.
Yes, the probability of an event is a number between 0 and 1 (both inclusive). You can write it as a fraction - in rational form or as a percentage.
1 in 6, or 0.17.
You write a number, not wright! It would be written as 75% of [the number].
690%
5300% ...
125 percent (1.25) as a mixed number is: 11/4
As a whole number, you can write 25 percent as 25%. As a part of a whole number, you'd write 25% of it as .25% or one quarter -- 1/4, of the whole number.
218.2%