The answer is 50%.
Well, honey, if 80% of California drivers wear seat belts, then the probability of one driver wearing a seat belt is 0.8. So, the probability of all three drivers wearing their seat belts would be 0.8 x 0.8 x 0.8, which equals 0.512 or 51.2%. So, there you have it, buckle up and enjoy the ride!
probability of 75 percent = 3/4
It is 67%.
It is 84.3%
78% I just had this question on apex
10%
Well, honey, if 80% of California drivers wear seat belts, then the probability of one driver wearing a seat belt is 0.8. So, the probability of all three drivers wearing their seat belts would be 0.8 x 0.8 x 0.8, which equals 0.512 or 51.2%. So, there you have it, buckle up and enjoy the ride!
The probability is 1 out of 36, or about 3%, I think.
10
The probability of 33.3 percent is 0.333.
To find the probability of it being windy given that it is not sunny, we can use conditional probability. The probability of it being not sunny is 70% (100% - 30% chance of sun). The probability of it being windy and not sunny is 40%. Therefore, the probability of it being windy given that it is not sunny is ( P(\text{Windy | Not Sunny}) = \frac{P(\text{Windy and Not Sunny})}{P(\text{Not Sunny})} = \frac{40%}{70%} \approx 0.57). Rounding to the nearest percent, the probability is approximately 57%.
probability of 75 percent = 3/4
It is 67%.
It is 84.3%
To get the answer to this question you need to work out what 30% of 80% is. To do this you need to divide 30, by 80, then multiply your answer by 100. 30/80=0.375, 0.375*100=37.5, 37.5 to the nearest percent is 38%
You multiply the probability by 100.
Refer back to the first clause. The answer is 50 per cent!